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marissa [1.9K]
3 years ago
8

Sophie is looking at a small particle through a microscope. It has unique proteins in its cell wall, but no nucleus. It is shape

d like a sphere. What is Sophie observing? A. a virus B. a bacterial cell C. an archaeal cell D. a host cell
Chemistry
1 answer:
Rudiy273 years ago
7 0

Answer:

C. an archaea cell

Explanation:

Both bacteria and archaea have a cell wall, but the bacteria cell wall has peptidoglycan. The archaeal doesn't have peptidoglycan, but some unique proteins. They both also don't have nuclei. A virus doesn't have a cell wall, and a host cell, if eukaryote, would have a nucleus.

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Differences between allotropy and isotopy​
raketka [301]

Answer:

Property of an element by virtue of which it exists in two or more forms which differ only in their physical properties is known as allotropy. Allotropes are the different physical forms in which the element can exist. Allotropes are different physical forms of the same element.

Also-

Allotropes are different forms of the same element in the molecular level. Isotopes are different forms of atoms of the same chemical element. The key difference between allotropes and isotopes is that allotropes are considered at the molecular level, whereas isotopes are considered at the atomic leve

Explanation:

~Hope this helps~

3 0
2 years ago
A calorimeter contains 280.0g of water at 13.5C. When 0.250g of a substance with a molar mass of 510.0g/mol is dissolved, the te
marin [14]

The change in heat is simply equal to:

change in heat ΔH = final enthalpy – initial enthalpy

ΔH = [280.25 g * 4.18J/gC * (17.5°C)] – [280 g * 4.18J/gC * 13.5°C]

ΔH = 4,699.89 J = 4.7 kJ

 

<span>Hence heat released is about 4.7 kJ</span>

8 0
3 years ago
In the formula for water H2O what is a subscript 2 indicate?
lara [203]

There are two atoms of hydrogen molecules.

8 0
3 years ago
Rules for naming compounds are beneficial to the scientific community.
blondinia [14]
Agree with the statement buddy
8 0
3 years ago
Read 2 more answers
50.00 mL of 0.10 M HNO 2 (nitrous acid, K a = 4.5 × 10 −4) is titrated with a 0.10 M KOH solution. After 25.00 mL of the KOH sol
boyakko [2]

Answer:

b. 3.35

Explanation:

To calculate the pH of a solution containing both acid and its salt (produced as a result of titration) we need to use Henderson’s equation i.e.

pH = pKa + log ([salt]/[acid])     (Eq. 01)

Where  

pKa = -log(Ka)        (Eq. 02)

[salt] = Molar concentration of salt produced as a result of titration

[acid] = Molar concentration of acid left in the solution after titration

Let’s now calculate the molar concentration of HNO2 and KOH considering following chemical reaction:

HNO2 + KOH ⇆ H2O + KNO2    (Eq. 03)

This shows that 01 mole of HNO2 and 01 mole of KOH are required to produce 01 mole of KNO2 (salt). And if any one of them (HNO2 and KOH) is present in lower amount then that will be considered the limiting reactant and amount of salt produced will be in accordance to that reactant.

Moles of HNO2 in 50 mL of 0.01 M HNO2 solution = 50/1000x0.01 = 0.005 Moles

Moles of KOH in 25 mL of 0.01 M KOH solution = 25/1000x0.01 = 0.0025 Moles

As it can be seen that we have 0.0025 Moles of KOH therefore considering Eq. 03 we can see that 0.0025 Moles of KOH will react with only 0.0025 Moles of HNO2 and will produce 0.0025 Moles of KNO2.

Therefore

Amount of salt produced i.e [salt] = 0.0025 moles       (Eq. 04)

Amount of acid left in the solution [acid] = 0.005 - 0.0025 = 0.0025 moles (Eq.05)

Putting the values in (Eq. 01) from (Eq.02), (Eq. 04) and (Eq. 05) we will get the following expression:

pH= -log(4.5x10 -4) + log (0.0025/0.0025)

Solving above we get  

pH = 3.35

5 0
3 years ago
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