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Nina [5.8K]
4 years ago
15

Create a story and describe the motion (in meters) of an object that has traveled a distance but has no displacement. Need Help

ASAP
Chemistry
1 answer:
vekshin14 years ago
3 0

Answer:

One complete revolution around a circular path.

Explanation:

Let us take the case of a car moving in a circular track of radius r metres.

In one revolution, the car covers the length(distance) equal to the perimeter of the circle.

In this case, distance traveled = 2\pir metres

But after one complete revolution, the car reaches the same position as it was at the beginning of the motion.

Hence, the initial and final points coincide or the car hasn't changed it's position w.r.t the initial point.

So in this case, the displacement is zero.

Hence, revolution of a car around a circular path is an example of an object traveling a distance but having no displacement.

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Consider the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g). If 0.02 moles of PCl5, 0.04 moles of PCl3, and 0.08 moles of Cl2 are combined
Furkat [3]

Answer:

The reaction quotient (Q) before the reaction is 0.32

Explanation:

Being the reaction:

aA + bB ⇔ cC + dD

Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where Q is the so-called reaction quotient and the concentrations expressed in it are not those of the equilibrium but those of the different reagents and products at a certain instant of the reaction.

The concentration will be calculated by:

Concentration=\frac{number of moles of solute}{Volume}

You know  the reaction:

PCl₅ (g) ⇌ PCl₃(g) + Cl₂(g).

So:

Q=\frac{[PCl_{3} ] *[Cl_{2} ] }{[PCl_{5} ]}

The concentrations are:

  • [PCl₃]=\frac{0.04 moles}{0.5 L} =0.08 \frac{moles}{L}
  • [Cl₂]=\frac{0.08 moles}{0.5 L} =0.16 \frac{moles}{L}
  • [PCl₅]=\frac{0.02 moles}{0.5 L} =0.04 \frac{moles}{L}

Replacing:

Q=\frac{0.08*0.16}{0.04}

Solving:

Q= 0.32

<u><em>The reaction quotient (Q) before the reaction is 0.32</em></u>

4 0
3 years ago
What volume of hydrogen will be produced at STP by the reaction of 67.3 g of tin with excess water according to the following re
VikaD [51]

Answer:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

Explanation:

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters

5 0
3 years ago
The regular sequence of growth and division that cells undergo is called the?
KIM [24]

Answer:

Cell cycle.

Explanation:

A cell can be defined as the fundamental or basic functional, structural and smallest unit of life for all living organisms. Some living organisms are unicellular while others are multicellular in nature.

A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.

Generally, cells have the ability to independently replicate themselves. These cells can be compared to the kind of structures found in a business or factory, where you have different workers performing different functions.

In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles and they include nucleus, cytoplasm, cell membrane, golgi apparatus, mitochondria, lysosomes, ribosomes, chromosomes, endoplasmic reticulum, vesicles, etc.

The regular sequence of growth and division that cells undergo is called the cell cycle. This cycle makes it possible for the cells found in living organisms to divide and produce new cells.

Basically, there are four (4) phases of the cell cycle and these are;

I. Prophase.

II. Metaphase.

III. Anaphase.

IV. Telophase.

3 0
3 years ago
If you had 24 moles of hydrogen gas how many moles of ammonia (NH3) would be produced?
dedylja [7]

Answer:

8

Explanation:

You are going to divide the 24 moles of H by the moles of H used in Ammonia. In this case 3

24/3=8

8 0
3 years ago
Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro
melamori03 [73]

<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For nickel:</u>

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol

For the given chemical reaction:

3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)

  • <u>For nickel (II) oxide:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from \frac{3}{3}\times 0.252=0.252mol of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g

  • <u>For aluminium:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from \frac{2}{3}\times 0.252=0.168mol of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

4 0
3 years ago
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