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4 years ago

If carbon monoxide is responsible for global warming

1 answer:

5 0

It may right but consequensely somehow the compounds formed by the CO2 causes so
We could also say that carbondioxide is responsible for global warming

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A 68.0 kg diver falls from rest into a swimming pool from a height of 4.90 m. It takes 1.46 s for the diver to stop after enteri

Natali5045456 [20]

Answer:

456.4 N

Explanation:

From conservation of energy, the potential energy is converted to kinetic energy hence

mgh=½mv²

Making v the subject then

$v=\sqrt {2gh}$

Where g is acceleration due to gravity and h is height whike v is final velocity. Substituting 4.9m for h and 9.81 m/s² for g then

$v=\sqrt {2\times 9.81\times 4.9}=9.80499872514015m/s\approx 9.8 m/s$

Change in momentum equals to the impulse.

Impulse, I= Ft

Change in momentum, ∆p= m(v-u)

Ft=m(v-u) making F the subject of formula then

$F=\frac {m(v-u)}{t}$

Where F is force in Newton, t is time in seconds, m is mass of diver, v and u are the final and initial velocities respectively.

Substituting 68 kg for m, 9.8 m/s for v, 0 m/s for u since it is initially at rest and 1.46 s for t

$F=\frac {68(9.8-0)}{1.46}=456.43835616438N\approx 456.4N$

7 0

3 years ago

Runner 1 has a velocity of 10 m/s west. Runner 2 has a velocity of 7 m/s east. From the frame of reference of runner 2, what is

Vsevolod [243]

Answer:

Explanation:

Runner 1 has velocity = 10 m/s west

runner 2 has velocity = 7 m/s east

From the frame of reference of runner 2, we can imagine runner 2 as standing still, and runner 1 moving away from him, towards the west with their combined velocity of

velocity = 10 m/s + 7 m/s = <em>17 m/s west</em>

5 0

3 years ago

Suppose the moon were held in its orbit not by gravity but by the tension in a massless cable. You are given that the period of

Ksenya-84 [330]

Answer:

Tension in the cable = 200.655 × 10^(18) N

Explanation:

The tension in the cable will be the force on the string which is caused by when it holds against the centripetal acceleration.

Now, the formula for centripetal acceleration is given by;

a = v²/R

Now, let's find the velocity.

The circumference is 2πR

We are given that R = 3.85 x 10^(8) m

So, Circumference = 2 × π × 3.85 x 10^(8) = 24.19 × 10^(8) m

We are told the period of the moon orbit is 27.3 days

Distance travelled per day = Circumference/ period

Distance travelled per day = (24.19 × 10^(8))/27.3 = 88608058.608 m/day

Now, a day has 24 hours = 24 × 60 × 60 = 86400 seconds

Thus,

Distance travelled per seconds =

88608058.608/86400 = 1025.556 m/sec

So, from a_c = v²/r,

a_c = 1025.556²/3.85x10^8

a_c = 0.00273 m/s²

Now, Force = Mass x Acceleration = ma

We are given mass = 7.35 x 10^(22) kg

Plugging in the relevant values, we have;

F = 0.00273 x 7.35 x 10^(22)

F = 200.655 × 10^(18) N

5 0

3 years ago

The input force of 29.3 N acting on the effort arm of a lever moves 1.7 m, which lifts a 1 N weight resting on the load arm a di

kolezko [41]

Hey this is for high school or middle school

7 0

3 years ago

A 320-g ball and a 400-g ball are attached to the two ends of a string that goes over a pulley with a radius of 8.7 cm. Because

Gnom [1K]

To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that

F = ma

Where,

m = mass

a = Acceleration (Gravitational acceleration when there is action over the object of the earth)

Torque, as we know, is the force applied at a certain distance, that is,

$\tau = F*d$

Where

F= Force

d = Distance

Our values are given as,

$m_1 = 0.32Kg$

$m_2 = 0.4Kg$

$d = 8.7*10^{-2}m$

Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say

$\tau = T_2-T_1$

$\tau = F_2*d-F_1*d$

$\tau = m_2g*d-m_1*g*d$

$\tau = (m_2-m_1)g*d$

$\tau = (0.4-0.32)(9.8)(8.7*10^{-2})$

$\tau = 0.068N\cdot m$

Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is $\tau = 0.068N\cdot m$

8 0

3 years ago