1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
9

1. What is the probability of rolling a five on one die three times in a row?

Chemistry
1 answer:
Bad White [126]3 years ago
7 0
1/6 x 1/6 x 1/6= solve the rest
You might be interested in
Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:
dem82 [27]

Answer:

The percent yield of the reaction is 62.05 %

Explanation:

Step 1: Data given

Volume of methane = 25.5 L

Pressure of methane = 732 torr

Temperature = 25.0 °C = 298 K

Volume of water vapor = 22.0 L

Pressure of H2O = 704 torr

Temperature = 125 °C

The reaction produces 26.0 L of hydrogen gas measured at STP

Step 2: The balanced equation

CH4(g) + H2O(g) → CO(g) + 3H2(g)

Step 3: Calculate moles methane

p*V = n*R*T

⇒with p = the pressure of methane = 0.963158 atm

⇒with V = the volume of methane = 25.5 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 298 K

n = (p*V) / (R*T)

n = (0.963158 * 25.5 ) / ( 0.08206 * 298)

n = 1.0044 moles

Step 4: Calculate moles H2O

p*V = n*R*T

⇒with p = the pressure of methane = 0.926316 atm

⇒with V = the volume of methane = 22.0 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 398 K

n = (p*V) / (R*T)

n = (0.926316 * 22.0) / (0.08206 * 398)

n = 0.624 moles

Step 5: Calculate the limiting reactant

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

H2O is the limiting reactant. It will completely be consumed (0.624 moles).

Methane is in excess. There will react 0.624 moles. There will remain 1.0044 - 0.624 moles = 0.3804 moles methane

Step 6: Calculate moles hydrogen gas

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

For 0.624 moles H2O we'll have 3*0.624 = 1.872 moles

Step 9: Calculate volume of H2 at STP

1.0 mol at STP has a volume of 22.4 L

1.872 moles has a volume of 1.872 * 22.4 = 41.9 L

Step 10: Calculate the percent yield of the reaction

% yield = (actual yield / theoretical yield) * 100 %

% yield = ( 26.0 L / 41.9 L) *100 %

% yield = 62.05 %

The percent yield of the reaction is 62.05 %

6 0
3 years ago
Read 2 more answers
Can you guys give some science fair project ideas(8th grade)
Anton [14]
Answer
i’m in 7th grade but for this years science fair i did, “ how does temperature affect the elasticity of rubber bands”

Guide a growing plant through a maze.
8th Grade Science Plant Maze KiwiCo

Prove that plants really do seek out the light by setting up a simple or complex maze. This is a simple 8th grade science project with really cool results.

Blow out a candle with a balloon.


Blowing up a balloon with baking soda and vinegar is the classic acids and bases experiment. Take it a step further by experimenting with the carbon dioxide it produces. (Don’t be afraid of fire in the science

Stand on a pile of paper cups.


Combine physics and engineering and challenge 8th grade science students to create a paper cup structure that can support their weight. This is a cool project for aspiring architects.

hope this helps and have a wonderful day :)
5 0
3 years ago
Which of the following is the correct set up AND answer to convert 6.25 x
BlackZzzverrR [31]

Answer:

Explanation:

How many mols do you have?

1 mol = 6.02 * 10^23 atoms

x mol = 6.25 * 10 ^32 atoms

1/x = 6.02*10^23 / 6.25 * 10^32        Cross multiply

6.02 * 10^23 * x = 1 * 6.25 * 10^32    Divide by 6.02 * 10^23

x = 6.25 * 10*32/ 6.02 ^10^23

x = 1.038 * 10^9 mols which is quite large.

Find the number of grams. (Use the value for copper on your periodic table. I will just use an approximate number.)\

1 mol of copper = 63 grams.

1.038 * 10^9 mols of copper = x

1/1.038 * 10^9 = 63/x         Cross multiply

x = 1.038 * 10^9 * 63

x = 6.54 * 10^10 grams of copper.

7 0
3 years ago
How many electrons will be in the valence of non- H atoms when they make covalent bonds?
NNADVOKAT [17]

Answer:

Please one time click here

Mark brainliest

8 0
2 years ago
A balloon is filled to a volume of 2.20L at a temperature of 22*C. The balloon is then heated to a temperature of 71*C. Find the
goldfiish [28.3K]

2.565L

Explanation:

  • Charles law states that the volume of an ideal gas at constant pressure is directly proportional to the absolute temperature.V/T=K

         V1/T1=V2/T2        

          Unit of Kelvin = 273.15

  • To get the absolute temperature, we need to convert the degree celsius temperature to kelvin.

          T1= 22+273.15= 295.15 K

          T2 = 71+273.15= 344.15 K

          V1 = 2.20 L

          V2 =?

          2.20/295.15=V2/344.15

          0.00745 x 344.15 = 2.565 L

Hence,  2.565 L is the new volume of the balloon.

3 0
3 years ago
Other questions:
  • What term describes a carbon atom that has four different groups bonded to it?
    8·1 answer
  • Can anyone solve these balanced chemical equations
    13·2 answers
  • Why do we slant the graduated cylinder before dropping the metal cylinder into it?
    14·1 answer
  • What is the diagram of 2CO2
    12·1 answer
  • What is the Ka of a 0.0326 M solution of hydrofluoric acid with a pH of 3.94?
    13·1 answer
  • If you mark me as a brain list ill mark you sooooooooo make a question and copy and paste this on it and let become brainlists
    13·2 answers
  • Cu + O2 --Cu2O
    9·1 answer
  • Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).
    11·1 answer
  • What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
    12·1 answer
  • If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3, what is the mass of the AgCl precipitate?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!