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Naya [18.7K]
3 years ago
13

Need help with this chem question thanks

Chemistry
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

The answer to your question is letter A.

Explanation:

Isomers are molecules that have the same molecular formula but have a different structure. The molecule from which are looking an isomer has 5 carbons and 1 double bond. Then we need to look for another molecule with these components.

A.- This molecule has 5 carbons and 1 double bond, This structure is an isomer of the first one.

B.- This molecule has 3 carbons and 1 double bond, it's not an isomer of the first structure.

C. This molecule has 4 carbons and 1 triple bonds, it's not an isomer of the first structure.

D. This molecule has 5 carbons but it doesn't have any double bond, then it's not an isomer of the first structure.

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Answer:

62.03 g/mol

Explanation:

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---
svet-max [94.6K]
  • No of protons=No of electrons=15
<h3>Mass no:-No of neutrons+No of protons </h3>

\\ \tt\longmapsto 15+16=31

Now

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Electronic configuration:-

\\ \tt\longmapsto 1s^22s^22p^63s^23p^3.

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\\ \tt\longmapsto XCl_3

or.

\\ \tt\longmapsto PCl_3

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What's the purpose of a compounds lab
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The purpose of a lab report is to organize and communicate what you did in your experiment.

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In the nuclear transmutation, 168O (?, α)137N, what is the bombarding particle? In the nuclear transmutation, O (?, )N, what is
xeze [42]

Answer:

The bombarding particle is a Proton

Explanation:

A Nuclear transmutation reaction occurs when radioactive element decay, usually converting them from one element/isotope into another element. Transmutation is the process which causes decay, generally, alpha or beta.

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16 + x = 13 + 4

x = 17 – 16 = 1, Hence we can say that x = ¹₁P

<u>¹⁶₈O + ¹₁P goes to ¹³₇N + ⁴₂He</u>

Here we can clearly see the bombarding particle is ¹₁P (proton). The ejected particle being ⁴₂He which is also known as an alpha particle

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