The distance separating two wave crests is known as the wavelength. The wavelength of the second laser, where its second maximum would be located, is 0.109375 mm.
Double slit interference (constructive) can be described by the equation dsinθ=m λ
Here, the order is (m), the wavelength is (), and the slit distance is (d).
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The laser's wavelength is d/8.
The slit separation is 0.500 mm in length.
Put the distance into consideration to determine the wavelength values as,
λ1=0.5 x 10⁻³/8
λ1=0.0625 x 10⁻³
Due to the second laser's wavelength, its second maximum would be at the same spot as the first laser's fourth minimum.
Therefore, we must first determine the fourth order minima as,
dsinθ= (4-1/2) λ1
dsinθ= (7/2) λ1
Using the second maxima, dsinθ= 2λ₂
Put the following value for in the equation above:
7/2λ1 = 2λ₂
7/2 x (0.0625 x 10⁻³) = 2λ₂
λ₂=0.000109375m.
Therefore, the wavelength of the second laser, where its second maximum would be located, is 0.109375 mm.
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