Ask question

Ask question

All categories

2 years ago

9

A gene carries the blank for the trait

1 answer:

Mamont248 [21]2 years ago

8 0

Information

Genes carry the __information___ that determines your traits, which are features or characteristics that are passed on to you — or inherited — from your parents. Each cell in the human body contains about 25,000 to 35,000 genes.

Hope this helps you :D

You might be interested in

A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circ

Mice21 [21]

Answer:

The net force is 91780.8 N.

Explanation:

mass, m = 8950 kg

Radius, R = 9.33 miles = 15015.2 m

Time, T = 0.123 h = 442.8 s

There are two forces acting on the plane.

Horizontal force is the centripetal force and the vertical force is the weight.

$Fx =m R w^2\\\\Fx = m R \frac{4\pi^2}{T^2}\\\\Fx = 8950\times 15015.2\times \frac{4\times 3.14\times 3.14}{442.8\times 442.8}\\\\Fx = 27030.8 N \\\\Fy = m g \\\\ Fy = 8950\times 9.8 \\\\Fy = 87710 N$

The net force is

$F = \sqrt{Fx^2 + Fy^2}\\\\F = \sqrt {27030.8^2 + 87710^2}\\\\F = 91780.8 N$

7 0

3 years ago

Two small insulating spheres with radius 3.50×10^−2m are separated by a large center-to-center distance of

Liula [17]

Answer:

Part (i) the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C

Part (ii) the direction of the electric field is towards the negative charge

Explanation:

Given;

+q = 3.93.90μC, r = 3.50×10⁻²m

-q = −2.40μC, r = 3.50×10⁻²m

magnitude of the electric field is experienced, midway between the spheres at a distance r, r = ¹/₂ × 0.51 = 0.255 m

Electric field due to point charge is given as;

$E = \frac{F}{q} = \frac{Kq^2}{qr^2} = \frac{kq}{r^2}$

K is coulomb's constant = 8.99 x 10⁹ Nm²/C²

The positive charge on positive x-axis and the negative charge is on negative x-axis.

part (a)

The electric field due to positive charge; +q = 3.93.90μC

$E_+ = \frac{kq}{r^2}\\\\E_+ = \frac{8.99 X10^9*3.9X0^{-6}}{0.255^2}\\\\E_+= 5.3919 X10^5\frac{N}{C}$

The electric field due to negative charge; -q = −2.40μC

$E_- = \frac{kq}{r^2}\\\\E_- = \frac{8.99 X10^9*2.4X0^{-6}}{0.255^2}\\\\E_-= 3.3181 X10^5\frac{N}{C}$

From superimposition theorem

The magnitude of the electric field is;

E = E₊ + E₋

E = (5.3919 × 10⁵ + 3.3181 × 10⁵) N/C

E = 8.71 × 10⁵ N/C

Therefore, the magnitude E of the electric field midway between the spheres is 8.71 × 10⁵ N/C

Part (b)

The direction of the electric field is towards the negative charge.

7 0

3 years ago

How much power is used if a force of 54 newtons is used to pull a wagon a distance of 10 meters in 6 seconds?

AnnZ [28]

First, calculate the work done: 54 x 10 = 540J.
Now calculate power: 540 / 6 = 90.
The answer is 90W.

Hope this helps.

7 0

3 years ago

Read 2 more answers

PLZ HELP!!!!!!! My favorite playground equipment is the swings. In 1-3 sentences explain a pattern of motion that u predict u'll

In-s [12.5K]

My favorite playground equipment is the swings.

4 0

3 years ago

Select all the correct ANSWERS.

MissTica

The ground exerts an equal force on the golf ball.

3 0

3 years ago