Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
True,According to Isaac Newton believes that Gravity is responsible for drawing attraction which is directly proportional to product of their masses but inversely proportional to the square of the distance between them.
Answer:
1: An electronic signal is the use of an electric current to encode information
2: Electronics: A message encoded by changing the voltage of an electric current.
3: I don't know :( Sorry
Explanation:
Answer:
dada given
speed is 35m/s
time is 5s
acceleration =?
from a=∆v/t
a= 35m/s÷5s
a=7m/s^2
how far
from
velocity = displacement/time
35m/s=d/5s
distance is 175m
