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VARVARA [1.3K]
3 years ago
9

Which of the following pairs of elements would form the covalent bond with the largest dipole moment? View Available Hint(s) Whi

ch of the following pairs of elements would form the covalent bond with the largest dipole moment?
a.Ge and O
b.H and P
c.In and F
d.B and N
Chemistry
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

In-F bond has the largest dipole moment.

Explanation:

Given the electronegativities:

Ge= 2.01

O= 3.44

H= 2.20

P= 2.19

In= 1.78

F= 3.98

B= 2.04

N= 3.04

The bond between Ge and O has an electronegativity difference:

ED= 3.44 - 2.01= 1.43

The bond between H and P has an electronegativity difference:

ED= 2.20 - 2.19= 0.01

The bond between In and F has an electronegativity difference:

ED= 3.98 - 1.78= 2.20

The bond between B and N has an electronegativity difference:

ED= 3.04 - 2.04= 1.00

As In-F bond has the largest electronegativity difference, this is the covalent bond with the largest dipole moment.

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Answer:

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The maximum height attained occurs at the two end points of her swing motion.  

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Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.

Hope this helps!

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Distillation is used to separate _____.
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Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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