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inysia [295]
3 years ago
8

How do fermentation reactions in oxygen-starved muscle cells and anaerobically grown yeast cells differ?

Chemistry
1 answer:
dedylja [7]3 years ago
8 0

In oxygen- starved muscle cells in anaerobic respiration lactic acid is formed while in anaerobic respiration by yeast cells it produces ethanol and carbon dioxide.

Explanation:

Respiration occurring in absence of oxygen in muscles leads to accumulation of lactic acid and very less amount of energy. This is fermentation process as the end product formed is lactic acid.

The process of fermentation takes place in yeast bacteria and oxygen starved cells of muscles.

The yeast can ferment simple sugars like glucose and fructose into ethyl alcohol and carbon dioxide.

In general human respiration is aerobic but during strenuous exercise, oxygen does not meet the demand of working out muscle, so they respire anaerobically and produce lactic acid and 2 ATP i.e very less compared to 38 molecules of ATP in aerobic respiration.

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On a cold morning, the smoke coming out of a chimney is observed to be in blue color. What could be the reason? Name the effect
nirvana33 [79]

Stack effect? I'm not totally sure about this...

Explanation:

Large amount of tiny particles of water droplets, dust and smoke are present on a misty day. These tiny particles in the air scatter blue colour of white light passing through it. When this scattered light reaches our eyes, the smoke appears blue.

6 0
3 years ago
Which of the following is an endothermic process?
Neporo4naja [7]

Hello There!

A Heat Pack is An Example Of A Endothermic Process.

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6 0
3 years ago
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Why aluminum in 1820 had more value than gold​
bonufazy [111]

Answer:

Aluminum had more value than gold in the 1820s, because it was harder to obtain. Hope this helped :)

4 0
2 years ago
Could anyone help me with question 3?
Masteriza [31]
What your question for number 3
8 0
3 years ago
Hurry please!
Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at 20^oC is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in \frac{27g}{9.02g}\times 100ml=299.33ml of water

The volume of water is 299.33 ml.

As we know that the density of water at 20^oC is 0.9982 g/ml

Now we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g

Therefore, the mass of of water present in the jar is, 298.79 g

5 0
3 years ago
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