Question

An eagle is flying above a mountain of height 2,700 m above sea level. Calculate the pressure on the eagle if the average density of air is 1.3 kg/m3,the atmospheric pressure at sea level is 76 cm Hg, and the density of mercury is 13,600 kg/m3.​

Answer 1

Answer:

The correct option is;

(A) 25.8 cmHg

Explanation:

The given parameters are;

The height of the mountain over which the eagle is flying = 2700 m

The average density of air, ρₐ = 1.3 kg/m³

The atmospheric pressure at sea level = 76 cmHg = 0.76 mHg

The density of mercury, $\rho _m$ = 13,600 kg/m³

The formula for pressure, p, is p = ρ·g·h

The pressure in the atmosphere = 13,600 × 0.76 × g = 10,336·g

The equivalent height of air is found as follows;

1.3 × g × h = 10,336·g

h = 10,336/1.3 = 7,950.769 meters

Therefore;

The pressure of the atmosphere at 2,700 meters, p₂₇₀₀ = (2,700/7,950.769) × 76 cm Hg

Which gives;

p₂₇₀₀ = 25.808 cmHg ≈ 25.8 cmHg.