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Elena L [17]
3 years ago
10

Does Mike wosowski blink or wink

Physics
2 answers:
aev [14]3 years ago
7 0

Answer:

both

Explanation:

GrogVix [38]3 years ago
6 0
Definitely both because of the one eye situation
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The bohr model of the atom addressed the problem of
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Force Problem: Four concurrent forces are applied to a 5 Kg mass: 50 N North, 25 N East, 35 N South, and 35 N West.
Kaylis [27]

A) Net horizontal force:
Fx= -35 + 25 + -10N

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Fy= 50 - 35 = 15N

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a=18/5=3.6m/s^2

C). Equilibriant force must be equal to the net force above
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6 0
1 year ago
Two loudspeakers S1 and S2, 2.20 m apart, emit the same single-frequency tone in phase at the speakers. A listener L is located
seropon [69]

Answer:

the lowest possible frequency of the emitted tone is 404.79 Hz

Explanation:

   Given the data in the question;

S₁ ←  5.50 m → L

↑

2.20 m

↓

S₂

We know that, the condition for destructive interference is;

Δr = ( 2m + \frac{1}{2} ) × λ

where m = 0, 1, 2, 3 .......

Path difference between the two sound waves from the two speakers is;

Δr = √( 5.50² + 2.20² ) - 5.50

Δr = 5.92368 - 5.50

Δr = 0.42368 m

v = f × λ

f = ( 2m + \frac{1}{2})v / Δr

m = 0, 1, 2, 3, ....

Now, for the lowest possible frequency, let m be 0

so

f = ( 0 + \frac{1}{2})v / Δr

f = \frac{1}{2}(v) / Δr

we know that speed of sound in air v = 343 m/s

so we substitute

f = \frac{1}{2}(343) / 0.42368

f = 171.5 / 0.42368

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Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz

5 0
3 years ago
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