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nika2105 [10]
3 years ago
11

Fred can create 20 animal balloons every 15 minutes. solve ratio table

Chemistry
1 answer:
DerKrebs [107]3 years ago
3 0

The number of animal balloons created in 15 minutes = 20

The number of animal balloons created in 1 minute = \frac{20}{15}

So, the number of animal balloons created in 6 minutes = \frac{20}{15}\times 6 = 8

And, the number of animal balloons created in 45 minutes = \frac{20}{15}\times 45 = 60

So, the solved ratio table will be:

15.20

6.8

45.60



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If 1.08 g of sodium sulfate reacts with an excess of phosphoric acid, how much sulfuric acid is produced?
vfiekz [6]

Answer:  0.745 g of H_2SO_4 will be produced from  1.08 g of sodium sulfate

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Na_2SO_4=\frac{1.08g}{142.04g/mol}=0.0076moles  

3Na_2SO_4+2H_3PO_4\rightarrow 2Na_3PO_4+3H_2SO_4

Na_2SO_4 is the limiting reagent as it limits the formation of product and H_3PO_4 is the excess reagent.

According to stoichiometry :

3 moles of Na_2SO_4 produce = 3 moles of H_2SO_4

Thus 0.0076 moles of Na_2SO_4 will require=\frac{3}{3}\times 0.0076=0.0076moles  of H_2SO_4

Mass of H_2SO_4=moles\times {\text {Molar mass}}=0.0076moles\times 98.1g/mol=0.745g

Thus 0.745 g of H_2SO_4 will be produced from  1.08 g of sodium sulfate

3 0
2 years ago
What would be a likely climatic outcome of rising ocean temperatures?
Kay [80]
I think your answer is D. However I’m not 100% sure.
7 0
3 years ago
I need help solving this for chemistry. Don’t know where to start:/
Juli2301 [7.4K]
1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

One ion Co²⁺   takes 2e⁻ to become Co⁰.
1 mol of Co²⁺  ions take 2 mole of e⁻ to become Co⁰, so
 0.30 mol Co²⁺  ions take mole of 0.60 mol e⁻ to become Co⁰

9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
8 0
3 years ago
What are the different acid bases
Alex

Answer:

different acids include acetic acid,lactic acid,tartaric acids DNA(deoxyribonucliec acid) .

different bases include calcium oxide Potassium hydroxide ,Sodium hydroxide and Barium hydroxide .

5 0
3 years ago
For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
levacccp [35]

Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

  • For entropy change for the surroundings = ΔS = ΔH/T
  • ΔS  = -251 kJ/mol / 298K
  • ΔS = -0.84KJ/mol.K or -842J/mol.K is the entropy change for the surroundings
8 0
3 years ago
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