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3 years ago

How long would it take you too run the 100m sprint if from rest you accelerate at 2m/s/s for the whole race?

Physics

1 answer:

fredd [130]3 years ago

4 0

Answer:

10 s

Explanation:

Given:

Δx = 100 m

v₀ = 0 m/s

a = 2 m/s²

Find: t

Δx = v₀ t + ½ at²

100 m = (0 m/s) t + ½ (2 m/s²) t²

t = 10 s

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What is perfect machine

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Answer:

Explanation:

A machine is which no part of the work done on the machine is wasted, is called an ideal or perfect machine

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3 years ago

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The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th

bagirrra123 [75]

The velocity of the wave on the string is given by

$v=\sqrt{\frac{T}{\frac{m}{L}}} \\ v=\sqrt{\frac{TL}{m}}$

Solving the above equation,

$v^2=\frac{TL}{m} \\ L=\frac{v^2m}{T}$

The frequency of the wave $f=300$ and wave length is $0.76$

The velocity is $v=(300)(0.76)=228$

Substituting numerical values,

$L=\frac{228^2(0.0059)}{200}\\ T=1.534$

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3 years ago

A light beam is traveling through an unknown substance. When it exits that substance and enters into air, the angle of reflectio

bogdanovich [222]

Answer:

0.79

Explanation:

Using Snell's law, we have that:

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°

=> 1.0003 * sin32 = n(2) * sin42

n(2) = (1.0003 * sin32) / sin42

n(2) = 0.79

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4 years ago

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Explanation:

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Because here Energy is released.

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3 years ago

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In a circuit with one 12.0 resistor, a current of 0.500 A is flowing. This circuit is powered by a single

Juliette [100K]

Answer:

6 V

Explanation:

In a circuit, the relationship between voltage, current and resistance is given by Ohm's law:

$V=RI$

where

V is the voltage

R is the resistance

I is the current

In this circuit, we have

$R=12.0\Omega$ is the resistance

I = 0.500 A

so we can find the voltage of the battery by using Ohm's law:

$V=(12.0 \Omega)(0.500 A)=6 V$

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3 years ago