Answer:
a)
b)
Explanation:
For this case we have the following frequency given:
We can convert this into Hz like this:
If we have a fundamental wave we need to satisfy the following condition:
If we solve for the wavelength we got:
We know that the velocity of the light is
And if we replace into the last formula we got:
Part b
For this case we can use the same formula but on this case the velocity of the sound at 20C is approximately 343 m/s, the frequency is given by:
We use the same wavelenght from the previous part
And if we replace the new values we got:
It does take on new set of proerties
Answer:
B
Explanation:
The top and bottom forces cancel each other. The left is more than the right so we "add" them --> -352+176=-176
-176(aka 176 to the left)
Because they’re far from each other and the J0523 has lower mass then the UY which is a red dwarf.
Answer: For the given process it is true that the balloon has a net charge on it, but the wall may be neutral (have no net charge).
Explanation:
When we tend to rub a balloon against a woolen sweater then it is possible that the balloon might stick to the wall. This might be due to the increase in number of electrons on the balloon and the wall gets positively charged.
Since, opposite charges tend to attract each other hence, the balloon will stick to the wall.
A neutral object also tends to acquire a certain charge when it is rubbed by a charged object.
Therefore, we can conclude that the balloon has a net charge on it, but the wall may be neutral (have no net charge).