Question

Two horizontal forces act on a 2.0kg chopping block that canslide over a frictionless kitchen counter, which lies in an xyplane. One force is F1= (3.0N)i + (4.0N)j. Find the acceleration ofthe chopp;ing block in unot-vector notation when the other forceis:
a) F2= (-3.0N)i + (-4.0N)j
b) F2= (-3.0N)i + (4.0N)j
c) F2=(3.0N)i + (-4.0N)j

Answer 1

Explanation:

Given that,

Mass of the block, m = 2 kg

(a) Force, $F=(3i+4j)\ N$

Acceleration,

$a=\dfrac{F}{m}$

$a=\dfrac{1}{2}(3i+4j)\ m/s^2$

(b) $F=(-3i-4j)\ N$

Acceleration,

$a=\dfrac{1}{2}(-3i-4j)\ m/s^2$

(c) $F=(-3i+4j)\ N$

Acceleration,

$a=\dfrac{1}{2}(-3i+4j)\ m/s^2$

(d) $F=(3i-4j)\ N$

$a=\dfrac{1}{2}(3i-4j)\ m/s^2$

Hence, this is the required solution.