The Electric field strength reduces or increases as the distance from the source increases or reduces respectively. It actually follows inverse square law.
The Electric Field strength reduces or increases by the square of the distance away from the source or toward the source respectively.
Answer:
a) v = 4.64 m / s
, b) t = 0.947 s
, c) t = 0.947 s
Explanation:
We will work on this exercise with vertical launch kinematics, let's start by calculating the height of the jumper in the SI system
y₀ = 5 ’(0.3048 m / 1’) + 7 ”(2.54 10-2 m / 1”) = 1.70 m
The distance they give is the height of the jump
y = 1.10 m
Let's use energy conservation
Starting point. On the floor
Em₀ = K = ½ m v²
Final point. Maximum height
Em_{f} = U = m g y
Em₀ =
½ m v² = m g y
v = √2gy
Let's calculate
v = √(2 9.8 1.10)
v = 4.64 m / s
b) Air time is the time to go up plus the time to go down, which is the same
For maximum height the speed is zero
v = v₀ - g t₁
t₁ = v₀ / g
t₁ = 4.64 /9.8
t₁ = 0.4735 s
The total time is
t = 2 t₁
t = 2 0.4735
t = 0.947 s
c) if it takes a distance of 0.40 to reach speed, what is the acceleration, as it stands on the floor its initial speed is zero
v² = v₀² + 2 a x
a = v² / 2x
a = 4.64²/2 0.40
a = 26.9 m / s²
Sir Isaac Newton, held the theory that light was made up of tiny particles<span>. In 1678, Dutch physicist, Christiaan Huygens, believed that light was made up of </span>waves<span>vibrating up and down </span>perpendicular<span> to the direction of the light travels, and therefore formulated a way of visualising wave propagation.</span>
Answer:
The extension of the refracted rays will intersect at a point. This point is known as the focal point. Notice that a diverging lens such as this double concave lens does not really focus the incident light rays that are parallel to the principal axis; rather, it diverges these light rays.
Explanation: