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ra1l [238]
3 years ago
5

Two horizontal forces act on a 2.0kg chopping block that canslide over a frictionless kitchen counter, which lies in an xyplane.

One force is F1= (3.0N)i + (4.0N)j. Find the acceleration ofthe chopp;ing block in unot-vector notation when the other forceis:
a) F2= (-3.0N)i + (-4.0N)j
b) F2= (-3.0N)i + (4.0N)j
c) F2=(3.0N)i + (-4.0N)j
Physics
1 answer:
TEA [102]3 years ago
4 0

Explanation:

Given that,

Mass of the block, m = 2 kg

(a) Force, F=(3i+4j)\ N

Acceleration,

a=\dfrac{F}{m}

a=\dfrac{1}{2}(3i+4j)\ m/s^2

(b) F=(-3i-4j)\ N

Acceleration,

a=\dfrac{1}{2}(-3i-4j)\ m/s^2

(c) F=(-3i+4j)\ N

Acceleration,

a=\dfrac{1}{2}(-3i+4j)\ m/s^2

(d) F=(3i-4j)\ N

a=\dfrac{1}{2}(3i-4j)\ m/s^2

Hence, this is the required solution.                                                

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