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S_A_V [24]
3 years ago
13

The frequency of a given region of the electromagnetic spectrum ranges from 3 × 1016 − 3 × 1019 hertz. Which type of wave is fou

nd in this region?
A. x-rays
B. ultraviolet rays
C. infrared waves
D. radio waves
Physics
1 answer:
yan [13]3 years ago
4 0

The most sensible answer is B

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The magnitude of Earth’s magnetic field is about 0.5 gauss near Earth’s surface. What’s the maximum possible magnetic force on a
vampirchik [111]

Answer:

F = 1.5 \times 10^{-16} N

this force is 1.68 \times 10^{13} times more than the gravitational force

Explanation:

Kinetic Energy of the electron is given as

KE = 1 keV

KE = 1 \times 10^3 (1.6 \times 10^{-19}) J

KE = 1.6 \times 10^{-16} J

now the speed of electron is given as

KE = \frac{1}{2}mv^2

now we have

v = \sqrt{\frac{2 KE}{m}}

v = 1.87 \times 10^7 m/s

now the maximum force due to magnetic field is given as

F = qvB

F = (1.6\times 10^{-19})(1.87 \times 10^7)(0.5 \times 10^{-4})

F = 1.5 \times 10^{-16} N

Now if this force is compared by the gravitational force on the electron then it is

\frac{F}{F_g} = \frac{1.5 \times 10^{-16}}{9.1 \times 10^{-31} (9.8)}

\frac{F}{F_g} = 1.68 \times 10^{13}

so this force is 1.68 \times 10^{13} times more than the gravitational force

4 0
3 years ago
Think about the electricity sent to your home from a power plant. How does the voltage of the electricity that leaves the plant
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C. High voltage to low voltage
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Answer:

The Current decreases

Explanation:

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A giant armadilo moving northward with a constant acceleration covers the distance between two points 60m apart in 6 seconds. It
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Acceleration is the rate of change of the velocity of an object that is moving. This value is a result of all the forces that is acting on an object which is described by Newton's second law of motion. To determine acceleration, we need to know the initial velocity and the final velocity and the time elapsed. From the given values, we need t o calculate for the initial velocity. We use some kinematic equations. We do as follows:

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60 = v0(6) + a(6)^2/2
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vf = v0 + at
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Solving for v0 and a,
v0 = 5 m/s
a = 1.7 m/s^2
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