Question

Consider a conical pendulum with a bob of mass m = 80.0 kg on a string of length L = 10.0 m that makes an angle of 5.0 degrees with the vertical. Determine the radial acceleration of the bob. (Hint: first calculate the tension using the net y- forces = 0 and use newton's second law of motion to find radial acceleration).

Answer 1

Answer:

0.8582 m/s^2

Explanation:

mass of the bob m = 80 kg

length of the string L= 10.0 m

angle made with the vertical θ= 5.0

let the force exerted by the string = T

from the FBD

T cosθ= mg

T cos 6°= 80×9.81

⇒T= $\frac{70\times9.81}{cos5}$

= 787.79 N

how horizontal component of tension $T_h$

$T_h= Tsin\theta$

=787.79 sin 5°= 68.66 N

Now, radial acceleration, $a_c= \frac{T_h}{m}$

= 68.66/80=  0.8582 m/s^2