Answer:
a)6.34 x W/m²
b)1.37 x W/m²
c) see explanation.
Explanation:
a)The relation of intensity'I' of the radiation and area 'A' is given by:
I= P/A
where P= power of sunlight i.e 3.9 x J
and the area of the sun is given by,
A= 4π => 4π
A=6.15 x m²
= 3.9 x / 6.15 x =><u> 6.34 x </u><u>W/m²</u>
b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space
A= 4π
Now R= 1.5 x m
A= 4π x 1.5 x =>2.83 x m²
The power that each square meter of Earths surface receives
= 3.9 x /2.83 x =><u>1.37 x </u><u> W/m²</u>
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c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.
Answer:
jk
Explanation:
Lets decompose the initial velocity into its components:
Vi = 2.25 m/s
Vix = Vi x cos(50)
Viy = Vi x sin(50) = 2.25 x sin(50) = 1.724
Then decompose the final velocity:
Vf = 4.65
Vfx = Vf x cos(120)
Vfy = Vf x sin(120) = 4.65 x sin(120) = 4.027
After that we can use:
Vfy = Viy + ay*t
ay = (Vfy - Viy)/t
ay = (4.027 - 1.724) / 8.33
ay = 0.276
Answer:
Part a)
the efficiency will be 100%
Part b)
for above condition internal resistance of the cell must be ZERO
Explanation:
Electric current supplied by the battery is given as
now the total power supplied by the cell is given as
power supplied to external load is given as
Part a)
If output power is adjusted to have maximum value then value of internal resistance must be ZERO
for same condition power given by the cell
so the efficiency will be 100%
Part b)
for above condition internal resistance of the cell must be ZERO
Explanation:
Given that,
The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.
(a) Capacitance of capacitor 1,
Capacitance of capacitor 2,
Capacitance of capacitor 3,
(b) The equivalent capacitance in series combination is :
Hence, this is the required solution.