Answer:
mass of the neutron star =3.45185×10^26 Kg
Explanation:
When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.
That is
![\frac{GM_{ns}}{R^2}= \omega^2 R](https://tex.z-dn.net/?f=%5Cfrac%7BGM_%7Bns%7D%7D%7BR%5E2%7D%3D%20%5Comega%5E2%20R)
M_ns = mass odf the netron star.
G= gravitational constant = 6.67×10^{-11}
R= radius of the star = 18×10^3 m
ω = 10 rev/sec = 20π rads/sec
therefore,
![M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}](https://tex.z-dn.net/?f=M_%7Bns%7D%3D%20%5Cfrac%7B%5Comega%5E2R%5E3%7D%7BG%7D%20%3D%20%5Cfrac%7B4%5Cpi%5E2%5Ctimes%2818%5Ctimes10%5E3%29%5E3%7D%7B6.67%5Ctimes10%5E%7B-11%7D%7D)
= 3.45185... E26 Kg
= 3.45185×10^26 Kg
Answer:
Explanation:
Electric field between plates of a parallel plate capacitor is uniform .
In a uniform electric field , relation between electric field and potential gradient is as follows
electric field = potential gradient [ E = - dV / dl ]
in the given case ,
dV = 51 V ,
dl = 4 cm
= 4 x 10⁻² m
E = 51 / 4 x 10⁻²
= 12.75 x 10² V / m
= 1275 V / m
Answer:
-10.8m/s^2
Explanation:
a=change in velocity/change in time
-27 m/s/2.5=10.8m/s^2
or if its not negative
27m/s/2.5=10.8m/s^2