Work Done = Force x Distance Moved
Work Done = 25 x 15 = 375 Joules
Given :
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.
To Find :
The coefficient of static friction between the box and the plane.
Solution :
Vertical component of force :

Horizontal component of force(Normal reaction) :

Since, box is on the verge of slipping :

Therefore, the coefficient of static friction between the box and the plane is 1.07.
Hence, this is the required solution.
It’s either C or D. let me know but I would do C!
Answer:
your in mr langfords class
Explanation:
bruh moment
True ..............................