The statement can't be true. Objects with different masses held at the same height don't have the same gravitational potential energy.
Using the formula: ΔY = V₀y * t + (1/2) * ay * t²
Solve for time and get: 1.968s
Then use: v = d/t in the x-direction and get: d = 3.936
Answer
Correct Answer is B,D, F and G
Explanation:
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(a)
The work done on the projectile is 9375 joule.
The work on the projectile is calculated as
W=F×d
=1250×7.5
=9375 joule
(b)
The speed of the projectile after 7.5 m is 27.38 m/s
First we need to find out the acceleration of the projectile
F=m×a
1250=25×a
a=50 m/
Now the velocity of the projectile after 7.5 m is calculated as
v^2=u^2+2a×s
v^2=0+2×50*7.5
v=27.38 m/s
Answer:
V = L A = L pi R^2 volume of wire
V = 50 cm * .01 cm^2 = .5 cm^3
d(density) = 3.5 gm / .5 cm^3 = 7.0 gm/cm^3
A micrometer caliper could measure the diameter of the wire.
