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Grace [21]
3 years ago
14

A water dwelling slug like animal

Physics
2 answers:
rusak2 [61]3 years ago
8 0
The answer you are looking for is a leech! 

Hope this helps!
Dominik [7]3 years ago
8 0
Hello There!

It is a leech.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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Find the electric field a distance z above a circular ring carrying a constant line charge. For extra credit you may derive the
lora16 [44]

Answer:

F = 8.23 × 10⁻⁸N

Explanation:

F= kq²/r²

k= 9×10⁹Nm²/C²

q= 1.6×10⁻¹⁹C

r= 5.29×10⁻¹¹m

F= 9×10⁹× (1.6×10⁻¹⁹)²/  (5.29×10⁻¹¹)²

F = 8.23 × 10⁻⁸N

4 0
3 years ago
The speed of a wave is 65 m/sec. if the wavelength os the wave is 0.8 meters. what is the spedd of this wave?
san4es73 [151]
The time of a wave is 65 m/sec. if the wavelength of the wave is 0.8 meters. what is the speed of this wave?

answer- the speed is 52
7 0
2 years ago
a peice of titanium metal has a mass of 67.5 gm and a volume of 15 cm cubed. what is the density od titanium?​
Nuetrik [128]

density=mass/volume

mass=67.5

volume=15cm cube

so

67.5/15

4.5g/cm cube

6 0
3 years ago
Read 2 more answers
A 3.30-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down the incline in 1.60 s.(a) fi
AnnZ [28]
<span>Mass of the block m = 3.3kg Angle of the slide = 30 degrees Distance the block slides s = 2.10 m Time taken to slide t = 1.6 s Initially in rest condition so initial velocity u = 0. We have an equation for distance s = (u x t) + (1/2) x (a t^2) s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56) 2.56a = 4.20 => a = 1.64 So the magnitude of the Acceleration a = 1.64 m/s^2</span>
8 0
3 years ago
What is the answer to this question
Studentka2010 [4]

Answer:

0.11 m/s

Explanation:

From the question given above, the following data were obtained:

Initial displacement (d1) = 1.09 m

Final displacement (d2) = 2.55 m

Time (t) = 12.8 s

Average velocity =?

Next, we shall determine the total displacement (i.e change in displacement). This can be obtained as follow:

Initial displacement (d1) = 1.09 m

Final displacement (d2) = 2.55 m

Total displacement = d2 – d1

Total displacement = 2.55 – 1.09

Total displacement = 1.46 m

Finally, we shall determine the average velocity of the beetle. This can be obtained as follow:

Total Displacement = 1.46 m

Total time (t) = 12.8 s

Average velocity =?

Average velocity = Total Displacement / Total time

Average velocity = 1.46/12.8

Average velocity = 0.11 m/s

Thus, the average velocity of the beetle is 0.11 m/s

6 0
3 years ago
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