Calculate the diffusion current density for the following carrier distributions. For electrons, use Dn = 35 cm2/s and for holes,
use Dp = 10 cm2/s. a. ; Jn = ______________________________________________ b. , at x = 0: Jp (0) = __________________________________ c. , at x = 2.5 µm: Jp (2.5 µm) = _______________________________________ d. , at x = 20 µm: Jp (20 µm) = _______________________________________________ e. , at x = 5 µm: Jn (5 µm) = _______________________________________________ n (x) = (1010 cm−3 ) 5 μm − x 5 μm
1 answer:
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Answer:
Elastic modulus of steel = 202.27 GPa
Explanation:
given data
long = 110 mm = 0.11 m
cross section 22 mm = 0.022 m
load = 89,000 N
elongation = 0.10 mm = 1 × m
solution
we know that Elastic modulus is express as
Elastic modulus = ................1
here stress is
Stress = .................2
Area = (0.022)²
and
Strain = .............3
so here put value in equation 1 we get
Elastic modulus =
Elastic modulus of steel = 202.27 × Pa
Elastic modulus of steel = 202.27 GPa
Answer:
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Explanation:
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