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3 years ago

What term best describes the difference in colors of the birds below?

Physics

1 answer:

katrin [286]3 years ago

5 0

Just tryna get points points points points points points

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The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,

madam [21]

Answer:

(b) 1:1

Explanation:

1. Formulae:

E = hf

E = h.v/λ

λ = h/(mv)

E = (1/2)mv²

Where:

E = kinetic energy of the particle
λ = de-Broglie wavelength
m = mass of the particle
v = speed of the particle
h = Planck constant

2. Reasoning

An alha particle contains 2 neutrons and 2 protons, thus its mass number is 4.

A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

$\dfrac{m_\alpha}{m_p}=4$

For the kinetic energies you find:

$\dfrac{E_\alpha}{E_p}=\dfrac{m_\alpha \times v_\alpha^2}{m_p\times v_p^2}$

$\dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4$

Thus:

$\dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}$

$m_\alpha v_\alpha=m_pv_p$

From de-Broglie equation, λ = h/(mv)

$\dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1$

5 0

3 years ago

The position-time equation for a cheetah chasing an antelope is:

pochemuha

Answer:

x = 1.6 + 1.7 t^2 omitting signs

a) at t = 0 x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0 V = 0

c) A = d^2 x / d t^2 = 3.4 (at t = 0 A = 3.4 m/s^2)

d) x = 1.6 + 1.7 * (4.4)^2 = 34.5 (position at 4.4 sec = 34.5 m)

4 0

2 years ago

1/012=1/0.05+1/d' hiiiiiiiiii

klasskru [66]

Correct question is;

1/0.12 = (1/0.05) + (1/d')

Answer:

d' = -1/700

Explanation:

1/0.12 = (1/0.05) + (1/d')

Let's rearrange to get;

(1/d') = (1/0.12) - (1/0.05)

(1/d') = (1/(12/100)) - (1/(5/100))

(1/d') = 100/12 - 100/5

Let's multiply through by 60 to get rid of the denominators on the right side;

> (1/d') = 500 - 1200

> (1/d') = -700

> d' = -1/700

8 0

2 years ago

Guys pa help...Sana po yong totoo...wag napo sumagot Kung do nman alam

rodikova [14]

Gdhootiytuyin bilhyffjoueriiggyi

6 0

3 years ago

A particular conductor has 3.0 × 10^27 mobile electrons per cubic meter. The material is in the shape of a cylinder of length 6.

irina1246 [14]

Answer:

Explanation:

Given

Length of cylinder $L=6 cm$

diameter of cylinder $d=1 cm$

Area of cross-section $A=\frac{\pi\times d^2}{4}$

$A=\frac{\pi \times 10^{-4}}{4}=7.855\times 10^{-5} m^2$

$Emf =2.5 V$

current $I=5 mA$

$Resistance=\frac{V}{I}=\frac{2.5}{5\times 10^{-3}}$

$R=500 \Omega$

R is also given by

$R=\rho \frac{L}{A}$

where $\rho =resistivity$

$\rho =\frac{RA}{L}=\frac{500\times 7.85\times 10^{-3}}{6}$

$\rho =0.654 \Omega -m$

6 0

3 years ago

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