Answer:
(a) = 4.19 x N, and its direction is towards .
(b) It must be placed inside a hollow shell.
Explanation:
Let, = 165 kg, = 465 kg, = 60 kg, and the distance between and is 0.340 m.
(a) Since is placed midway between and , then its distance to both masses is 0.170 m.
From the Newton's law of universal gravitation,
F =
Where all variables have their usual meaning.
Then,
a. = -
=
= 2.25 x N
= 6.44 x N
∴ = = 6.44 x - 2.25 x
= 4.19 x N
The net force exerted by the two masses on the 60 kg object is 4.19 x N.
(ii) // = // - //
= 6.44 x - 2.25 x
(iii) The direction of the net force is to the right i.e towards .
(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.
c
a vector quantity has both magnitude and direction
B.) 100 N is the CORRECT answer
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