<span>c. They help discard some myths about objects in space.
When we learn something new, then we know more stuff,
and that helps us avoid ignorance and superstition.
The REAL question is:
</span><span>Why should we continue to send robotic spacecrafts,
and NOT spacecrafts piloted by people ?</span>
Answer:
+1.46×10¯⁶ C
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C
Force (F) = 0.615 N
Distance apart (r) = 0.750 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Charge 2 (q₂) =?
The value of the second charge can be obtained as follow:
F = Kq₁q₂ / r²
0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²
0.615 = 236700 × q₂ / 0.5625
Cross multiply
236700 × q₂ = 0.615 × 0.5625
Divide both side by 236700
q₂ = (0.615 × 0.5625) / 236700
q₂ = +1.46×10¯⁶ C
NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C
Answer:
4200 Joules
Explanation:
Work done =force x distance
From the question , we’re given f =350N ,
d = 12m
Using the above formula, we have
Workdone = 350 x 12
= 4200 Joules
Lett me come back imma translate this... and then ill come to help
Answer:
move the wire loops closer
Explanation:
because the closer t they are the more concentrated the energy is in that specific area
