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Alona [7]
2 years ago
14

Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca

rt accelerates at 5 m/s^2. What is the friction force resisting the pull?

Physics
2 answers:
sashaice [31]2 years ago
5 0

Answer:

0.5 N

Explanation:

(0.6 kg)(9.8 m/s^2) = 5.88 N

(0.6 kg)(5 m/s^2) = 3 N

4 N - 3 N = 1 N

1 N/5.88 N = 0.17

(0.17)(3 N) = 0.51 N which rounds to 0.5 N

LenKa [72]2 years ago
4 0

Answer:gjv

Explanation:

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Answer:

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4 0
3 years ago
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
dalvyx [7]

Answer:

Explanation:

a )  V = 3 cos(0.5t)

differentiating with respect to t

dv /dt = -3 x .5 sin0.5t

= -1.5 sin0.5t.

acceleration = - 1.5 sin 0.5t

when t = 3 s

acceleration = - 1.5 sin 1.5

= - 1.496 ms⁻²

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