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Alona [7]
3 years ago
14

Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca

rt accelerates at 5 m/s^2. What is the friction force resisting the pull?

Physics
2 answers:
sashaice [31]3 years ago
5 0

Answer:

0.5 N

Explanation:

(0.6 kg)(9.8 m/s^2) = 5.88 N

(0.6 kg)(5 m/s^2) = 3 N

4 N - 3 N = 1 N

1 N/5.88 N = 0.17

(0.17)(3 N) = 0.51 N which rounds to 0.5 N

LenKa [72]3 years ago
4 0

Answer:gjv

Explanation:

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