1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alona [7]
3 years ago
14

Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca

rt accelerates at 5 m/s^2. What is the friction force resisting the pull?

Physics
2 answers:
sashaice [31]3 years ago
5 0

Answer:

0.5 N

Explanation:

(0.6 kg)(9.8 m/s^2) = 5.88 N

(0.6 kg)(5 m/s^2) = 3 N

4 N - 3 N = 1 N

1 N/5.88 N = 0.17

(0.17)(3 N) = 0.51 N which rounds to 0.5 N

LenKa [72]3 years ago
4 0

Answer:gjv

Explanation:

You might be interested in
starting from rest , a formula one car accelerates uniformly at 25m\s2 for 30secs. what distance does it cover in the last one s
Anestetic [448]

The distance covered in the last second of motion is 737.5 m

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use the suvat equations.

First of all, we have to find the velocity of the car when the last second of motion starts, that is the velocity of the car after t = 29 s. We can use the equation:

v = u + at

where

u = 0 is the initial velocity

a=25 m/s^2 is the acceleration

Substituting t = 29 s,

v=0+(25)(29)=725 m/s

Now we can find the distance covered in the last second of motion by using

s=ut+\frac{1}{2}at^2

where

u = 725 m/s is the velocity at the beginning of the last second

t = 1 s is the time interval considered

a=25 m/s^2 is the acceleration

Substituting,

s=(725)(1)+\frac{1}{2}(25)(1)^2=737.5 m

Note that the acceleration of 25 m/s^2 is not realistic for a car, but I still have used the data of the problem.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
3 years ago
An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
Arisa [49]

Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

              = 1/2 (6 X 15)

              = 1/2 (90)

              = 45 meters

Hence, the object traveled 45 meters.

4 0
3 years ago
Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
Sonbull [250]

Answer:

<em>work done in pumping the entire fuel is 466587 J</em>

<em></em>

Explanation:

weight of the gasoline per volume = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 2 m

height of the tractor tank above the top of the tank = 5 m

work done in pumping fuel to this height = ?

First, we find the volume of the fuel

since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>

<em>Also, we assume that the fuel completely fills the tank.</em>

volume of a cylinder = \pi r^{2}l

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x 1.5^{2} x 2 = 14.139 m^3

we then find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 14.139 = 93317.4 N

work done = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 93317.4 x 5 = <em>466587 J</em>

8 0
3 years ago
Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0
Svetllana [295]

Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

i-direction:

m_1u_{1i}+m_2u_{2i}=m_1v_{1i}+m_2v_{2i}\\v_{2i} = \frac{m_1u_{1i}+m_2u_{2i}-m_1v_{1i}}{m_2}=\frac{(2\cdot 15-2\cdot10+2\cdot5)kg\frac{m}{s}}{2kg}=10\frac{m}{s}

j-direction:

m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}

Answer: Final velocity is: (10i + 15j) m/s

Change in the kinetic energy:

\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J

Answer: The system lost 500J worth of kinetic energy in the collision

4 0
3 years ago
HELP PLEASEEE
dedylja [7]
The temperature will (A) Decrease.
3 0
3 years ago
Other questions:
  • If a 2 kg ball traveling at 10 m/s hits a wall and stops in 0.03 seconds, then how much force will the ball experience?
    13·1 answer
  • A ___________ spreads from one machine to another rapidly without human action
    5·2 answers
  • A merry-go-round at a playground is a circular platform that is mounted parallel to the ground and can rotate about an axis that
    8·1 answer
  • To get the whole circle, you run t from 0 to 2 π. Use this information to confirm that the circumference of a circle of radius r
    7·1 answer
  • NEED ANSWER ASAP PLEASE!!!!
    10·1 answer
  • 1. Calculate the velocity of a 0.8 kg kitten with a forward momentum of 5 kg*m/s.
    12·1 answer
  • train engine of mass 4500 kg is connected by a rope to boxcar A. Boxcar A is connected by a second rope to boxcar B, which is co
    12·1 answer
  • Tech A says that an overdrive gear ratio means the input gear turns faster than the output gear. Tech B says that overdrive rati
    7·1 answer
  • An escalator carries you from one level to the next in an airport terminal. The upper level is 4.4m above the lower level, and t
    5·1 answer
  • jonatha want to put ketchup o​​​​​n his hamburger.he truns the ketchup bottle at an angle toward his plate and smacks the bottom
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!