Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
rt accelerates at 5 m/s^2. What is the friction force resisting the pull?
2 answers:
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Answer:
Acceleration,
Explanation:
Given that,
Height from a ball falls the ground, h = 17.3 m
It is in contact with the ground for 24.0 ms before stopping.
We need to find the average acceleration the ball during the time it is in contact with the ground.
Firstly, find the velocity when it reached the ground. So,
u = initial velocity=0 m/s
a = acceleration=g
It is in negative direction, u = -18.41 m/s
Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.
So, the average acceleration of the ball during the time it is in contact is .