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soldi70 [24.7K]
3 years ago
14

Yo can someone find me an e-boy?

Engineering
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
I got a friend how old are you and are you ok dating a bi guy
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The Acme tool is aligned to the work with: A. A square B. The eye C. An Acme tool gage D. A center gage
kotegsom [21]

Answer:

(c) an acme tool gage

Explanation:

with the help of an acme tool we measure the pitch of a screw thread it is used as reference for finding the pitch of the thread it is also called an inspection tool is aligned to work with an acme tool gage it is also used for gage the internal and external threaded product. it is also used for grinding and setting tools it is mainly work 29° thread angle

8 0
3 years ago
The kinetic energy correction factor depends on the (shape — volume - mass) of the cross section Of the pipe and the (velocity —
butalik [34]

Answer:

The kinetic energy correction factor the depends on the shape of the cross section of the pipe and the velocity distribution.

Explanation:

The kinetic energy correction factor take into account that the velocity distribution over the pipe cross section is not uniform.  In that case, neither the pressure nor the temperature are involving and as we can notice, the velocity distribution depends only on the shape of the cross section.

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3 years ago
6) Describe the differences between the troposphere and stratosphere.
vodka [1.7K]

Answer:

frejfru8758u37

Explanation:

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8 0
2 years ago
Which branch of engineering most closely relates to mechanical engineering?
Rus_ich [418]

Answer:

C

Explanation:

I COULD be wrong, i'm not sure but im confident its c

4 0
3 years ago
A horizontal curve on a two-lane road is designed with a 2,300-ft radius, 12-ft lanes, and a 65-mph design speed. Determine the
Ierofanga [76]

Answer:

distance = 22.57 ft

superelevation rate = 2%

Explanation:

given data

radius = 2,300-ft

lanes width = 12-ft

no of lane = 2

design speed = 65-mph

solution

we get here sufficient sight distance SSD that is express as

SSD = 1.47 ut + \frac{u^2}{30(\frac{a}{g}\pm G)}     ..............1

here u is speed and t is reaction time i.e 2.5 second and a is here deceleration rate i.e 11.2 ft/s² and g is gravitational force i.e 32.2 ft/s² and G is gradient i.e 0 here

so put here value and we get

SSD = 1.47 × 65 ×2.5  + \frac{65^2}{30(\frac{11.2}{32.2}\pm 0)}

solve it we get

SSD = 644 ft  

so here minimum distance clear from the inside edge of the inside lane is

Ms = Rv ( 1  - cos (\frac{28.65 SSD}{Rv}) )        .....................2

here Rv is = R - one lane width

Rv = 2300 - 6 = 2294 ft

put value in equation 2 we get

Ms = 2294 ( 1  - cos (\frac{28.65 \times 664}{2294})  )  

solve it we get

Ms = 22.57 ft

and

superelevation rate for the curve will be here as

R  = \frac{u^2}{15(e+f)}  ..................3

here f is coefficient of friction that is 0.10

put here value and we get e

2300 = \frac{65^2}{15(e+0.10)}

solve it we get

e = 2%

3 0
3 years ago
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