Answer:
The smallest radius at the junction between the cross section that can be used to transmit the torque is 0.167 inches.
Explanation:
Torsional shear stress is determined by the following expression:
Where:
- Torque, measured in .
- Radius of the cross section, measured in inches.
- Torsion module, measured in quartic inches.
- Torsional shear stress, measured in pounds per square inch.
The radius of the cross section and torsion module are, respectively:
Where is the diameter of the cross section, measured in inches.
Then, the shear stress formula is now expanded and simplified as a function of the cross section diameter:
In addition, diameter is cleared:
If and , then:
The smallest radius at the junction between the cross section that can be used to transmit the torque is 0.167 inches.
CORRECTLY PLACED:
Large-lite glazing requires consideration of the following (select all that apply)
a. glazing must be supported without imparting stresses.
b. glazing must be supported against wind loads.
c. gaskets must separate glazing and frame.
d. glazing must be vacuum-insulated e. weep holes must be provided in the horizontal mullions.
Answer: a, b, c and e.
Explanation:
When large-lite glazing is done, options a, b, c and e must be considered. But vacuum-insulation isn't necessary, so option d. isn't part of the considerations.
Answer:
0.00116
Explanation
The tensile modulus is the measure of the elastic deformation that a material has undergo.
While elastic strain is define as form of strain in which a body return to its original length after the removal of the force .
Strain s expressed as
Where e is the strain, A is the area, F is the applied force and E itensile modulus
From the data given,
Force, F=40,000
Area=πr^2
and the tensile modulus E=110GPa
If we insert values we arrive at
Hence the strain experienced by the material is 0.00116
Answer:
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