Answer:
At steady state output will be 2
Explanation:
We have given transfer function 
Input is unit step so 
We know that 
, here 
, is output
So output 
Taking 12 common from denominator
Now using partial fraction
On comparing coefficient A=4 and B = -2
Putting the values of A and B in Y(S)
Now taking inverse la place
Steady state means t tends to infinite
So output at steady state = 
Answer:
Explanation:
Given that solid circular rod rotates at constant speed and neglecting losses throughout the system, power is calculated as the product of torque and angular speed. That is to say:
There is a formula that relates torque with shear stress:
Where 
is the torsion module, whose formula for a solid circular cross section is:
The tension module is calculated herein:
Maximum allowed torsion is found by isolating it from shear stress equation:
Then, maximum transmissible power is determined directly:
Answer:
how are supposed to help when you can't do anything?
Answer: (a). E = 3.1656×10³⁴ √k/m
(b). f = 9.246 × 10¹² Hz
(c). Infrared region.
Explanation:
From Quantum Theory,
The energy of a proton is proportional to the frequency, from the equation;
E = hf
where E = energy in joules
h = planck's constant i.e. 6.626*10³⁴ Js
f = frequency
(a). from E = hf = 1 quanta
f = ω/2π
where ω = √k/m
consider 3 quanta of energy is lost;
E = 3hf = 3h/2π × √k/m
E = (3×6.626×10³⁴ / 2π) × √k/m
E = 3.1656×10³⁴ √k/m
(b). given from the question that K = 15 N/m
and mass M = 4 × 10⁻²⁶ kg
To get the frequency of the emitted photon,
Ephoton =hf = 3h/2π × √k/m (h cancels out)
f = 3h/2π × √k/m
f = 3h/2π × (√15 / 4 × 10⁻²⁶ )
f = 9.246 × 10¹² Hz
(c). The region of electromagnetic spectrum, the photon belongs to is the Infrared Spectrum because the frequency ranges from about 3 GHz to 400 THz in the electromagnetic spectrum.
