Answer:

Explanation:
The equation for kappa ( κ) is

we can find the maximum of kappa for a given value of b using derivation.
As b is fixed, we can use kappa as a function of a

Now, the conditions to find a maximum at
are:


Taking the first derivative:








This clearly will be zero when

as both are greater (or equal) than zero, this implies

The second derivative is




We dcan skip solving the equation noting that, if a=b, then

at this point, this give us only the first term

if a is greater than zero, this means that the second derivative is negative, and the point is a minimum
the value of kappa is



Answer:
a)48900 metros
b)0.36875 metros
c)75634 metros
d)9.876 metros
Explanation:
Hola, para resolver debemos convertir unidades utilizando equivalencias
a) 48.9 km
1 kilometro = 1000 metros
48.9 x 1000 = 48900 metros
b) 36.875 cm
1 centímetro =0.01 metros
36.875 x 0.01 = 0.36875 metros
c) 756,34 hm
1 hectómetro= 100 metros
756.34 x 100 = 75634 metros
d) 9876 mm
1 milímetro = 0.001 m
9876 x 0.001 = 9.876 metros
(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.
(b) The acceleration of the child-wagon system is 0.33 m/s².
(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.
<h3>
Net force on the third child</h3>
Apply Newton's second law of motion;
∑F = ma
where;
- ∑F is net force
- m is mass of the third child
- a is acceleration of the third child
∑F = 96 N - 75 N - 12 N = 9 N
Thus, the system of interest if the acceleration of the child in the wagon is to be calculated are;
- the wagon
- the children outside the wagon
<h3>Free body diagram</h3>
→ → Ф ←
1st child friction wagon 2nd child
<h3>Acceleration of the child and wagon system</h3>
a = ∑F/m
a = 9 N / 27 kg
a = 0.33 m/s²
<h3>When the frictional force is 21 N</h3>
∑F = 96 N - 75 N - 21 N = 0 N
a = ∑F/m
a = 0/27 kg
a = 0 m/s²
Learn more about net force here: brainly.com/question/14361879
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