In simpler terms, a proton and neutron weigh 1 amu (atomic mass unit) each.
The nucleus has 15 protons and 18 neutrons. Since a proton's and a neutron's weight is only 1 amu, we can simply add the number of protons and neutrons to find the total mass of the nucleus:
The nucleus' mass is 33 amu.
Answer:
The electric field outside the sphere will be .
Explanation:
Given that,
Radius of solid sphere = R
Charge = q
According to figure,
Suppose r is the distance between the point P and center of sphere.
If be the volume charge density,
Then, the charge will be,
.....(I)
Consider a Gaussian surface of radius r.
We need to calculate the electric field outside the sphere
Using formula of electric field
Put the value from equation (I)
Hence, The electric field outside the sphere will be .
