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jekas [21]
4 years ago
14

What is your hypothesis (or hypotheses) for this experiment?

Physics
2 answers:
mariarad [96]4 years ago
7 0

Answer:

mr or ms please type ur question fully please

svetoff [14.1K]4 years ago
7 0
What do we need to make a hypothesis on?
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A car moves 4m in 2s. The speed is_____.<br><br>(t/d)​
wariber [46]

Answer:

2m/s.

Explanation:

Speed = Distance / Time

= 4m / 2s

= 2m/s.

6 0
3 years ago
Read 2 more answers
What kind of variation is there in the mechanical energy as the cart rolls down the ramp? Does this agree with your prediction?
Harlamova29_29 [7]

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         W_{nc} = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

6 0
3 years ago
What form of energy breaks glass
yan [13]
While breaking glass with sound is an interesting trick it really takes a lot of effort vibrations diminishes do you to energy being carried away by the sound waves.
3 0
4 years ago
¿Alguien que me pueda dar las respuestas a las siguientes preguntas?
taurus [48]
Anskskskskskdbdbdbds
6 0
4 years ago
c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

  • v = 20 + (5 \times 30)

  • v = 20 + 150

  • v = 170 \:  \: m/s

Velocity after 30 seconds = 170 m/s

4 0
3 years ago
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