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3 years ago

What is the term used by particular kind of matter Called??

Chemistry

1 answer:

weqwewe [10]3 years ago

3 0

Answer:

$\boxed{\mathrm{substance}}$

Explanation:

The term used by particular kind of matter is called substance.

A substance is a particular kind of matter because it has physical properties.

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Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3

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Answer:

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2 years ago

Which weak acid solution has the greatest percent ionization? which weak acid solution has the greatest percent ionization? 0.14

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Answer:

0.0140 M H₂C₆H₆O₆.

Explanation:

We should mention the relation: Ka = α²C,

Where, Ka is the dissociation constant of the acid.

α is the degree of ionization of the acid.

C is the concentration if the acid.

The percent of ionization (α %) = α x 100.

α = √Ka/C

∴ α is inversely proportional to the concentration of the acid.

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2 years ago

Look at the equation for a displacement reaction below. What lost electrons in the reaction? Give the full name, not the symbols

garri49 [273]

Answer:

Cupric ions

Explanation:

In the single displacement reaction shown, the cupric ions lost two electrons.

Cu²⁺ + 2e⁻ → Cu

The replacement of a metallic ion in solution by a metal atom higher in the activity series than than the metal in solution falls into this category of reactions.

Since Zn higher in the series, it displacements the cupric ions.

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2 years ago

Determine the number of moles within a sample of 10g of propane(C3H8). Round your answer to 2 decimal places with proper units.

a_sh-v [17]

Given :

10 gram sample of propane( C₂H₈ ).

To Find :

The number of moles of propane in given sample.

Solution :

Molecular mass of propane, M = (2 × 12) + ( 1 × 8 ) gram/mol

M = 32 gram/mol

We know, number of moles is given by :

Number of moles, n = m/M

n = 10/32 mol

n = 0.3125 mol

Therefore, number of moles in given sample is 0.3125 mol.

7 0

2 years ago

The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil

o-na [289]

Answer :

The equilibrium favors NO and $Br_2$ .

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

$2NO(g)+Br_2(g)\rightarrow 2NOBr(g)$

The value of equilibrium constant for the above equation is $K_c=1.3\times 10^{-2}$ .

The value of $K_c$ that means equilibrium lies to the left side. Thus, the equilibrium favors NO and $Br_2$ .

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) $2NOBr(g)\rightarrow 2NO(g)+Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_1}=\frac{1}{K_c}$

$K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9$

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) $NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_2}=(\frac{1}{K_c})^{1/2}$

$K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77$

Thus, the value of equilibrium constant for this reaction is, 8.77

7 0

2 years ago

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