calculate the electric field strength between two parallel plates separated by 0.50 cm, across which is a potential of 12 volts.
1 answer:
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Answer:
The correct option is: B that is 1/2 K
Explanation:
Given:
Two carts of different masses, same force were applied for same duration of time.
Mass of the lighter cart =
Mass of the heavier cart =
We have to find the relationship between their kinetic energy:
Let the KE of cart having mass m be "K".
and KE of cart having mass m be "K1".
As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.
Numerical analysis.
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Now,
Kinetic energies and their ratios in terms of momentum or impulse.
KE (K) of mass m.
⇒ ...equation (i)
KE (K1) of mass 2m.
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⇒ ...equation (ii)
Lets divide K1 and K to find the relationship between the two carts's KE.
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The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.