Answer:
c =four significant figures = 3003
f = Four significant figures = 3820
d =(i) three significant figures = 450
d =(ii) Six significant figures = 35.0445
b = significant figures = 59.0001
e = five significant figures = 67000
Explanation:
c = 0.03003 kg
four significant figures = 3003
f = 3.8200 × 10³ L
Four significant figures = 3820
d =(i) 0.00450 m and (ii) 35.0445 g
(i) three significant figures = 450
(ii) Six significant figures = 35.0445
b = 59.0001 cm
six significant figures = 59.0001
e = 67000
five significant figures = 67000
The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.
Zero between the non zero digits are consider significant like 104 consist of three significant figures.
The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.
