Answer is: the solution is saturated.
Solubility of potassium chloride (KCl) on 20°C is 34.2 grams in 100 grams of water, so in 200 grams of water will dissolve two times more salt (68.4 g).
Saturated solution contains the maximum concentration of a solute dissolved in the solvent (usually water) and if extra solute is add to saturated solution, that solute will not dissolve.
The amount of solute that can be dissolved in a solvent depends of chemical composition, temperature and pressure.
Answer:
1552.83J Released
Explanation:
1. mass/m=225
Initial temp:86C, final:32.5C
Changed Temp: 32.5-86= -53.5C
s=0.129 J/gC
Formula: q= m times s times changed Temp.
q=(225)(0.129)(-53.5)
q= -1552.83 J
q=1552.83 J Released
Answer:
4.3 × 10²¹ atoms
Explanation:
Step 1: Calculate the moles corresponding to 0.24 g of CaCO₃
The molar mass of CaCO₃ is 100.09 g/mol.
0.24 g × (1 mol/100.09 g) = 2.4 × 10⁻³ mol
Step 2: Calculate the moles of oxygen in 2.4 × 10⁻³ moles of CaCO₃
The molar ratio of CaCO₃ to O is 1:3. The moles of O are 3/1 × 2.4 × 10⁻³ mol = 7.2 × 10⁻³ mol
Step 3: Calculate the number of O atoms in 7.2 × 10⁻³ moles of O
We will use Avogadro's number: there are 6.02 × 10²³ atoms of O in 1 mole of atoms of O.
7.2 × 10⁻³ mol × (6.02 × 10²³ atoms/1 mol) = 4.3 × 10²¹ atoms
question no 1 answer is compounds
Answer : The mass of 
is, 9.64 grams.
Explanation : Given,
Mass of 
= 54.6 g
Molar mass of = 17 g/mol
Molar mass of = 2 g/mol
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react to give 3 moles of
So, 3.21 mole of react to give 
mole of
Now we have to calculate the mass of
Therefore, the mass of is, 9.64 grams.
