Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g
52
Explanation:
We need to understand and apply the rules of significant figures when carrying out addition operations to solve this problem:
Rules of significant figures:
- Non-zero digits are always significant in a given number
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion is significant.
- Any leading zero in a decimal is significant.
In addition, the answer of the sum is given to the least number of significant digits of the given numbers:
44.2124
+ 0.81
+ 7.335
sum 52.3574
Now the least number of significant figure is 2 as seen in 0.81
we round the sum up to 52
learn more:
Significant numbers brainly.com/question/6384538
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Answer:
It is widely believed that Buddhism entered China via the Silk Road under the Han Dynasty. After trade and travel was established with the Yuezhi, who by that time were forced southward toward India, Yuezhi monks began to travel with the merchant caravans; preaching their religion along the Silk Road.
Explanation:
i got this from google
Answer:
The standard enthalpy of formation of HgO is -90.7 kJ/mol.
Explanation:
The reaction between Hg and oxygen is as follows.
From the given,
Molar mass of HgO = 216.59 g/mol
Mass of HgO decomposed = 18.5 g
Amount of heat absorbed = 7.75 kJ
From the reaction,
The standard enthalpy of formation = 
During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.
For the formation of 1 mol of HgO , 90.7 kJ of energy is release
Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol
