Answer:
SOH CAH TOA
(Sine,opposite,Hypotenuse) - SOH
(Cosine, adjacent, Hypotenuse) - CAH
(Tangent,opposite,adjacent) - TOA
Step-by-step explanation:
Answer:
8.5 hrs
Step-by-step explanation:
-A 75th percentile mathematically means that 75% of the time data points are below that value and 25% of the time are above that value.
-We plot the given our data {3 12 2 3 5} to determine the 75th percentile
#We can use
to plot our boxplot.
-From the plot, we find our 75th percentile to be 8.5 hrs
Hence, 75% of the time the number of hours spent to prepare was less than 8.5hrs.
Answer:
y = x - 6
Step-by-step explanation:
We want to write a line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
First, we need to find the slope, which is just the change in the y-coordinates divided by the change in the x-coordinates:
slope = m = 
Our equation now looks like this: y = x + b
Now, to find the y-intercept, let's use one of the points provided and plug those values of x and y into the incomplete equation we have to solve for b:
0 = 6 + b ⇒ b = -6
So, the equation is: y = x - 6.
Hope this helps!
Answer: tens
Step-by-step explanation: the number 2 is in the tens place because 6,025= 6 is in the thousands place 0 is in the hundredths place 2 is in the tens place and 5 is in the ones place
PLEASE MARK BRAINLIEST
Answer:
The Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft
Step-by-step explanation:
Given:
Number of skaters = 30
Area for each skater = 40 sq ft
We need to find the dimension of rectangular ring the are going to build.
Now we know that they building the skating ring such that they all can use at same time.
Hence if the all use at same time then we will find the total area first.
Total area can be calculated by multiplying Number of skaters with area required for each skaters.
Framing the equation we get;
Total area = 
Hence The total area of the rectangular ring would be 1200 sq. ft.
Now we know that Total area is equal to product of length and width.

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30
Hence the Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft