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melomori [17]
3 years ago
6

How many milliseconds are in 3.5 seconds

Chemistry
2 answers:
Ne4ueva [31]3 years ago
5 0
Its 3,500 milliseconds since its 1,000 milliseconds to 1 second
Ad libitum [116K]3 years ago
3 0
3,500 miliseconds are in one second :)
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The moon is 250,000 miles away. How many inches is it from earth?
Lapatulllka [165]

Answer:

1.584e10 = 15,840,000,000,000

Explanation:

250,000 miles

multiply the length value by 63360

25e4 x 63360

= 1.584e10

3 0
3 years ago
Read 2 more answers
Which is a complex molecule?<br><br> a. H2<br><br> b. Ne<br><br> c. Co<br><br> d. H20
eimsori [14]

Explanation:

d.

h{}^{2} o

3 0
3 years ago
When the glucose transport maximum is reached, _______.?
n200080 [17]
Glucose is extracted in the urine and all of the glucose is reabsorbed. 
8 0
3 years ago
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Amanda [17]

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

7 0
2 years ago
Determine the products of this unbalanced reaction: Select all that
inn [45]

Answer:

Ba3N2

Explanation:

valency of barium is+2and nitrogen is-3.

4 0
3 years ago
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