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alex41 [277]
4 years ago
12

Mr. Smith brings home 7 animals for his 7 children. Each child will adopt a pet to be her or his own. There are 4 different cats

(a Siamese, a Persian, a Calico, and a Minx), 2 different dogs (a Poodle and a Golden Retriever), and a goldfish. Anna and Betty refuse to take care of the goldfish, and Charlie and Danny insist on having cats. The other 3 kids are easier to please -- they'll take anything. In how many ways can Mr. Smith give the children pets?
Mathematics
1 answer:
ExtremeBDS [4]4 years ago
5 0
There are 4 cats, 2 dogs and 1 goldfish for a total of 7 animals. These animals should be distributed to each of Mr. Smith's children. But we must note of the restrictions. 

This is the solution for the problem:

2(7C6) + 2(7C4) + 3(7C1)

How is this so? The first term stand for Anna and Betty, hence, 2. Each of them must choose 6 out of the 7 animals (except for goldfish). That's why it's written as '7C6' which is combination of 6 out of 7. It stands for nCr, or 'r' objects out of 'n'. The equation for that is n!/[r!(n-r)!]. The second term is for Charlie and Danny who gets 4 cats out of the 7 animals. And lastly, the other 3 would get the three last pet available.

Solving the equation, the answer is 105 ways.
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A certain brand of dinnerware set comes in three colors: red, white, and blue. Twenty percent of customers order the red set, 45
denis23 [38]

Answer:

a) 0.20

b) 0.45

c) 0.65

d) Yes

e) Yes

f) Z = X + Y (except when X = 1 and Y = 1)

This is because the successes of X and Y are mutually exclusive events but their failures aren't. X and Y cannot both be 1.

Step-by-step explanation:

Probability of a red set = 20% = 0.20

Probability of a white set = 45% = 0.45

Probability of a blue set = 35% = 0.35

Probability of the single set being a red or white set = 20% + 45% = 65% = 0.65

P(X=1) = 0.20, P(X=0) = 1 - 0.2 = 0.80

P(Y=1) = 0.45, P(Y=0) = 1 - 0.45 = 0.55

P(Z=1) = 0.65, P(Z=0) = 1 - 0.65 = 0.35

a) pX = P(X=1) = 0.20

b) pY = P(Y=1) = 0.45

c) pZ = P(Z=1) = 0.65

d) Since only one order is being considered at a time, it isn't possible to order red & white set in a single set, hence, both X and Y cannot both be successes (equal to 1) at the same time. But they can both be failures (both equal to 0) if a blue set is ordered. The successes of X and Y are mutually exclusive events but their failures aren't

e) Is pZ = pX + pY

pX = 0.2, pY = 0.45, pZ = 0.65

Hence, this statement is correct!

f) Z = X + Y

Let's check all the probabilities

when X = 1 and Y = 1, Z = 1

1 ≠ 1 + 1

when X = 0 and Y = 1, Z = 1

1 = 0 + 1

when X = 1 and Y = 0, Z = 1

1 = 1 + 0

when X = 0 and Y = 0, Z = 0

0 = 0 + 0

Hence, Z = X + Y (except when X = 1 and Y = 1)

This is because the success of X and Y are mutually exclusive events but their failures aren't.

8 0
3 years ago
Bernardo is converting a fraction, StartFraction a Over b EndFraction, to a percent. Both a and b are whole numbers and not equa
anyanavicka [17]

Answer:

Percent = \frac{100a}{b}\%

Step-by-step explanation:

Given

\frac{a}{b}

Required

Convert to fraction

To do this, we simply multiply the fraction by 100%

This gives:

Percent = \frac{a}{b} * 100\%

Percent = \frac{a * 100}{b}\%

Percent = \frac{100a}{b}\%

The expression cannot be further simplified.

Take for instance the fraction is: \frac{2}{5}

Using the same analysis, the percentage would be:

Percent = \frac{2}{5} * 100\%

Percent = \frac{2 * 100}{5}\%

Percent = \frac{200}{5}\%

Percent = 40\%

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Answer:

The answer is "\sqrt{12} is not a perfect square".

Step-by-step explanation:

12 is not a perfect square because it is the natural number, and no other natural number would square the number 12, that's why it is not a perfect square.

If we calculate the square root of \sqrt{12}. so, it is will give 2\sqrt{3} that is not a perfect square root which can be described as follows:

\Rightarrow \sqrt{12}= \sqrt{2\times 2\times 3}

            = \sqrt{2^2\times 3}\\\\= 2\sqrt{3}\\\\

\bold{\sqrt{12}} is not a perfect square root.

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Answer:

the true math statements are a and c

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Answer:

Your answer is

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