A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction
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Answer:
The force exerted by the biceps is 143.8 kgf.
Explanation:
To calculate the force exerted by the biceps, we calculate the momentum in the elbow.
This momentum has to be zero so that her forearm remains motionless.
Being:
W: mass weight (6.15 kg)
d_W= distance to the mass weight (0.425 m)
A: weight of the forearm (2.25 kg)
d_A: distance to the center of mass of the forearm (0.425/2=0.2125 m)
H: force exerted by the biceps
d_H: distance to the point of connection of the biceps (0.0215 m)
The momemtum is:
The force exerted by the biceps is 143.8 kgf.
Answer:
The value is
Explanation:
Generally the moon's radial acceleration is mathematically represented as
Here is the angular velocity which is mathematically represented as
substituting for T(i.e the period of the moon ) we have
=>
From the question r(which is the radius of the orbit ) is evaluated as
substitute for R and
H
=>
So