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Eduardwww [97]
3 years ago
15

A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction

is 0.27.
If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.
Physics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

Explanation:

Velocity at the bottom of height h

= √2gh

deceleration on rough horizontal surface

= μg , μ is coefficient of friction

= .27 x 9.8

= 2.646 m / s²

v² = u² - 2as

0 = 2gh - 2 x 2.646 x 19

h =  2 x 2.646 x 19  / 2 x 9.8

= 5.13 m  

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The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

V_{f}=V_{o}+at (1)  

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Where:  

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b) Begining with (1):

V_{f}=0+at (3)  

V_{f}=at=(9.8 m/s^{2})(1.2 s) (4)  

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a) Substituting (5) in (2):

(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d (6)  

Clearing d:

d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})} (7)  

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5 0
2 years ago
Help not to sure with this one need help plz asap​
DiKsa [7]

A is the answer for the problem

4 0
2 years ago
Read 2 more answers
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