Question

A child sleds down a frictionless hill with vertical drop h. At the bottom is a level stretch where the coefficient of friction is 0.27.
If she slides 19 m across the level stretch, what's h? Express your answer with the appropriate units.

Answer 1

Answer:

Explanation:

Velocity at the bottom of height h

= √2gh

deceleration on rough horizontal surface

= μg , μ is coefficient of friction

= .27 x 9.8

= 2.646 m / s²

v² = u² - 2as

0 = 2gh - 2 x 2.646 x 19

h =  2 x 2.646 x 19  / 2 x 9.8

= 5.13 m