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Radda [10]
3 years ago
7

[25 pts] When a 14.2g sample of a compound containing only mercury and oxygen is decomposed, 13.2g of Hg is obtained. What is th

e percent composition of this compound?
% Hg=
% O=
EXPLAIN (in words) how you got your answers:


​
Chemistry
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

% composition of Hg = 93 %

% composition of O = 7 %

Explanation:

Data Given:

mass of total sample = 14.2 g

mass of mercury (Hg) = 13.2 g

percent composition of Hg =

percent composition of O =

Solution:

First find mass of oxygen

As this compound only have two components that is oxygen and mercury

So

upon decomposition it gives 13.2 g mercury

now to find mass of oxygen we have to subtract mass of mercury from total mass of sample

                 Mass of oxygen =  Total mass of sample - mass of Mercury

                 Mass of oxygen =  14.2 g - 13.2 g

                 Mass of oxygen =  1 g

Now to find percent composition of Hg and Oxygen

% composition = component mass / total mass of sample x 100. . . .(1)

For % composition of mercury Hg

Put values in equation 1

             % composition of Hg = 13.2 g / 14.2 g x 100

               % composition of Hg = 93%

For % composition Oxygen (O)

Put values in equation 1

             % composition of O = 1 g / 14.2 g x 100

               % composition of O = 7 %

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charle [14.2K]
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s =  154.9 mol/L
6 0
3 years ago
PLS HELP ASAP i really need an answer a correct one
nata0808 [166]

Answer: 67.23 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles of methane}=\frac{48g}{16g/mol}=3moles

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy = \frac{22.4}{1}\times 3=67.23L

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6 0
3 years ago
The formula for chlorine acid is
fenix001 [56]

The correct terminology for chlorine acid is Hydrochloric Acid. The formula for that is HCl. This is because H has an ionic charge of +1 and Cl has an ionic charge of -1. Thus, they will combine to form HCl. Also, H is in front because almost all acids will have H in front.

5 0
4 years ago
A fuel-air mixture is placed in a cylinder fitted with a piston. The original volume is 0.310-L. When the mixture is ignited, ga
Soloha48 [4]

Answer:

V_2=11.35L

Explanation:

Knowing that the system is at constant pressure, the energy balance is:

\Delta H=Q-W

If all the energy (enthalpy of combustion) is transformed into work:

\Delta H=-W

Work:

W=-\int_{V1}^{V2}P*dV

W=-P*(V_2-V_1)

\Delta H=P*(V_2-V_1)

Calculating:

935J=84659 Pa*(V_2-3.1*10^{-4}m^3)

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3 0
3 years ago
the molar solubility of Zn(OH)2 is 5.7x 10^-3 mol/L at a certain temperature. Calculate the value of Ksp for Zn(OH)2 at this tem
Alex

Answer:

Ksp = 7.4x10⁻⁷

Explanation:

Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.

Ksp of Zn(OH)₂ is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

Ksp = [Zn²⁺] [OH⁻]²

And the molar solubility, X, is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

                 ⇄ X + 2X

<em>Because X are moles of substance dissolved.</em>

<em>Ksp = </em>[X] [2X]²

Ksp = 4X³

As molar solubility, X, is 5.7x10⁻³mol/L:

Ksp = 4X³

Ksp = 4 (5.7x10⁻³mol/L)³

<h3>Ksp = 7.4x10⁻⁷</h3>

5 0
3 years ago
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