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Tasya [4]
4 years ago
5

3. Which equation shows the relationship between the Kelvin and Celsius temperature scales? K = 273 – °C K = °C + 273 K = °F + 2

73 K = °C + °F
Physics
1 answer:
Alborosie4 years ago
7 0

Answer: K=\°C+273.15

Explanation:

The Kelvin (K), is the unit of temperature of the scale created by the British physicist William Thomson (Lord Kelvin) in 1848, <u>taking as a base the Celsius scale</u>, establishing the zero point for this scale in the absolute zero which is in -273.15\°C.

This was achieved by observing that when a gas cools, its volume decreases proportionally to its temperature. That is, <u>for each degree of temperature that the gas decreases, its volume also decreases by a certain percentage. </u>

After which, Kelvin made the calculations and it turned out that at a temperature of -273.15\°C the volume of the gas would be zero (theoretically).

It should be noted that the Kelvin is the unit of temperature of the International System of Units and that although the scale starts at absolute zero (theoretical), in which no molecule should move, in reality it is not so, because according to quantum physics, at this temperature the molecules retain a residual movement.

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How much pressure is created by a circular piston that is 0.24 meter in diameter
Vedmedyk [2.9K]

Answer:

4000 N/m²

Explanation:

Area = πr²

Area = π x 0.12² (diameter/2)

Area = 0.05 m²

Pressure = force/area

Pressure = 200/0.05

Pressure = 4000 N/m²

Hope this helps!

8 0
3 years ago
Which of the following explains how ions conduct electricity in a solution?
IrinaK [193]

Explanation:

you should give options to find out

5 0
3 years ago
Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A
Annette [7]

The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Impulse:

The effect of applied force acting for a very small interval of time is known as Impulse.

Given data:

The initial magnitude of the force on Ball A is, F = 50 N.

The time interval for the applied force on Ball A is, t = 1.25 s.

And the impulse at initial on ball A is, I = 62.5 N-s.

Now, if force on ball A doubles, which means new magnitude of force is,

F' = 2F

F' = 2 × 50

F' = 100 N

For same time interval, the new impulse on Ball A is given as,

I' = F' × t

Solving as,

I' = 100 × 1.25

I' = 125 N-s

Taking the ratio of both the impulses as,

I' / I = 125/62.5

I' = 2 I

Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Learn more about the impulse here:

brainly.com/question/904448

7 0
3 years ago
PLZ HELP DUE IN 10 MINUTES
likoan [24]

Answer:50%

Explanation: put it you are in a hurry

6 0
3 years ago
Scientists observe an approaching asteroid that is on a collision course with
nasty-shy [4]

Answer:

The approximate velocity the rocket must have to stop the asteroid completely after the collision is;

C. -324 m/s

Explanation:

The parameters of the asteroid and the rocket are;

The mass of the asteroid, m₁ = 11,000 kg

The initial velocity with which the asteroid is approaching Earth, v₁ = 50 m/s

The mass of the rocket, m₂ = 1700 kg

The initial velocity of the rocket = v₂

The final velocity of the combined asteroid and rocket after the collision, v₃ = 0 m/s

By the law of conservation of linear momentum, we have;

The total initial momentum = The total final momentum

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Substituting the known values, we get;

11,000 kg × 50 m/s + 1,700 kg × v₂ = (11,000 kg + 1,700 kg) × 0 m/s

11,000 kg × 50 m/s + 1,700 kg × v₂ = 0

∴ 1,700 kg × v₂ = -11,000 kg × 50 m/s

v₂ = (-11,000 kg × 50 m/s)/(1,700 kg) = -323.529412 m/s ≈ -324 m/s

The approximate initial velocity the jet must have to completely stop the asteroid after the collision is -324 m/s.

3 0
3 years ago
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