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3 years ago

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A consultant has proposed that a pulse-jet baghouse with bags that are 15 cm in diameter and 5 m in length. Estimate the net num

ber of bags required if the manufacturer’s recommended air-to-cloth ratio for aggregate plants in 0.05 m/s, and a requirement that 1/8 of the bags are off-line for cleaning

1 answer:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

0,5 bags

Total number of bags = 0.5 + 4 = 4.5 bags or 5 bags

Explanation:

Convert 15cm to meters = 15/100 = 0.15m

Flow rate Q = Area x velocity

= π d x v

= π (0.15) x 1

= 0.4712

A = Q/v = 0.4712/ 0.05

=<u> 9.435 m^2</u>

<u></u>

The net number of bags = A/π dh

= 9.425/π (0.15)(5)

= <u>4 bags </u>

<u></u>

Requirement that 1/8 of the bags are off-line for cleaning

= Net number of bags / 8

= 4/8

= <u>0.5 bag or 1bag</u>

<u></u>

<u>Total number of bags </u>

<u>= 4bags + 1bag </u>

<u>= 5bags </u>

<u></u>

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