Answer:
Chemistry is used in forensic science to uncover information from physical evidence.
Hope this helps
C! The clownfish hide in the sea anemones for protection
Answer:
The freezing point of the solution is - 4.39 °C.
Explanation:
We can solve this problem using the relation:
<em>ΔTf = (Kf)(m),</em>
where, ΔTf is the depression in the freezing point.
Kf is the molal freezing point depression constant of water = -1.86 °C/m,
density of water = 1 g/mL.
<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>
m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.
<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>
<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>
<em>∴ The freezing point of the solution is - 4.39 °C.</em>
Answer:
0.29 mol/L
Explanation:
Its density is 1.029 g/ml so in a liter (1000 mL) there is 1029 g of solution, but only 5% is dextrose.
0.05x1029=51.45
So in a liter of D5W solution there is 51.45 g of dextrose.
Dextrose molar mass iss 180.156 g/mol, so in 51.45 g of dextrose there is
51.45/180.156=0.29 mol
In one liter of solution there is 0.29 mol of dextrose, so the molarity of such solution is 0.29 mol/L.
