Explanation:
the correct empirical formula for C6H12O6 is CH2O...
hope it will help....
Mass spectrometry was discovered by Francis Aston, a British Physicist, in 1919. This involves separating mixtures of substances into their components and transforming them into beams of particles and subsequently, bending them with the use of electricity and magnetism to come up with a spectrum that is inherently unique for every individual atoms for easy identification.
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Answer:</h3>
Al₂(SO₄)₃
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Explanation:</h3>
We are given percentage composition of elements in a compound;
- Aluminium is 15.77%
- Sulfur is 28.11 %
- Oxygen is 56.12%
We are required to calculate the empirical formula of the compound.
- Assuming the mass of the compound is 100 g then the masses of the elements is;
Aluminium = 15.77 g
Sulfur = 28.11
Oxygen = 56.12
We can determine the number of moles of each;
Moles of Aluminium = 15.77 g ÷ 26.98 g/mol
= 0.585 moles
Moles of sulfur = 28.11 g ÷ 32.07 g/mol
= 0.877 moles
Moles of Oxygen = 56.12 g ÷ 16.0 g/mol
= 3.5075 moles
- But, the empirical formula is the simplest whole number ratio of elements in a compound.
- Therefore; we need to get the ratio of moles of the above elements;
Aluminium : Sulfur : Oxygen
0.585 mol : 0.877 mol : 3.5075 mol
0.585/0.585 : 0.877/0.585 : 3.5075/0.585
1 : 1.5 : 6
But, we need whole number ratios, therefore;
= (1 : 1.5 : 6 ) × 2
= 2 : 3 : 12
Therefore; the formula of the compound is Al₂S₃O₁₂
The compound is written as Al₂(SO₄)₃
Thus, the empirical formula of the compound is Al₂(SO₄)₃
<span>Obviously only one of the H's was replaced as the product showed one mole of water So the ratio is 1 to 1.Moles of NaOH used Molarity x volume = 0.1 x0.015(L) = 0.0015 moles
Mass of acid used is 0.0015 x 204 = 0.306g
moles MM
hopefully this helps</span>
