Explanation:
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Answer: C) 0.020 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
![Molality=\frac{n\times 1000}{W_s}](https://tex.z-dn.net/?f=Molality%3D%5Cfrac%7Bn%5Ctimes%201000%7D%7BW_s%7D)
where,
n = moles of solute
= weight of solvent in g
Mole fraction of
is =
i.e.
moles of
is present in 1 mole of solution.
Moles of solute
= ![3.6\times 10^{-4}](https://tex.z-dn.net/?f=3.6%5Ctimes%2010%5E%7B-4%7D)
moles of solvent (water) = 1 -
= 0.99
weight of solvent =![moles\times {\text {Molar mass}}=0.99\times 18=17.82g](https://tex.z-dn.net/?f=moles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.99%5Ctimes%2018%3D17.82g)
Molality =![\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020](https://tex.z-dn.net/?f=%5Cfrac%7B3.6%5Ctimes%2010%5E%7B-4%7D%5Ctimes%201000%7D%7B17.82g%7D%3D0.020)
Thus approximate molality of
in this solution is 0.020 m
One of the best buffer choice for pH = 8.0 is Tris with Ka value of 6.3 x 10^-9.
To support this answer, we first calculate for the pKa value as the negative logarithm of the Ka value:
pKa = -log Ka
For Tris, which is an abbreviation for 2-Amino-2-hydroxymethyl-propane-1,3 -diol and has a Ka value of 6.3 x 10^-9, the pKa is
pKa = -log Ka
= -log (6.3x10^-9)
= 8.2
We know that buffers work best when pH is equal to pKa:
pKa = 8.2 = pH
Therefore Tris would be a best buffer at pH = 8.0.
When
1-Bromopropane is treated with
methoxide it undergoes
SN² Reaction. The product formed is
Methyl Propyl Ether. This type of reaction is very important in synthesizing
Asymmetric ethers. The alkoxides are oftenly generated by reacting Alcohols with sodium metal, which on elimination of Hydrogen gas produces corresponding alkoxide. The reaction of given statement is as follow,