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Ilya [14]
3 years ago
6

A girl, moving at 8.8 m/s on in-line skates, is overtaking a boy moving at 4.3 m/s as they both skate on a straight path. The bo

y tosses a ball backward toward the girl, giving it speed 11.4 m/s relative to him. What is the speed of the ball relative to the girl, who catches it?
Physics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:16.5 m/s

Explanation:

Given

Velocity of boy(v_b)=4.3 m/s

velocity of girl(v_g)=8.8 m/s

velocity of ball relative to boy(v_{Bb})=11.4 m/s backward

Now We have to find velocity of ball relative to girl

Representing it in vector form

v_b=4.3\hat{i}

v_g=8.8\hat{i}

v_{Bb}=-11.4\hat{i}

and

v_{Bb}=v_B-v_b

v_B=v_{Bb}+v_b

v_B=-11.4\hat{i}+4.3\hat{i}=-7.1\hat{i}

therefore velocity of ball relative to girl

v_{Bg}=v_B-v_g=-7.1\hat{i}-8.8\hat{i}=-16.5\hat{i}

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