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3 years ago

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Chemistry

2 answers:

Leni [432]3 years ago

7 0

Answer:

Um what

Explanation:

There is no danger

azamat3 years ago

5 0

For part 1, just copy them off of the periodic table. For example, element 1 is Hydrogen, and its symbol is H

Elements on the left usually lose electrons and elements on the right tend to gain them. Noble gases have no charge.

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Some distilled water is added to an empty beaker. a gram of copper (ii) nitrate is added to the beaker and while the water is be

Xelga [282]

Copper ions, nitrate ions, and water is in the beaker

6 0

3 years ago

Chlorofluorocarbons such as CCl2F and CCI,F, have been linked to ozone depletion in Antarctica. In 1994, these gases were found

Ilya [14]

Answer:

a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³

Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³

B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³

Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³

Explanation:

Using the ideal gas equation:

PV = nRT

Further explanations are found in the attachment below.

4 0

4 years ago

If you have 600g of nitroglycerin, how many moles do you have?<br><br> help please

aleksandr82 [10.1K]

Answer:

600

Explanation:

there's 1 mole in every nitroglycerin

I think

5 0

3 years ago

A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin

laila [671]

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

3 0

3 years ago

How many moles of aspartame are present in 4.50 mg of aspartame?

Alekssandra [29.7K]

Answer:- $1.53*10^-^5mol$ .

Solution:- Aspartame is a artificial sweetener with molecular formula $C_1_4H_1_8N_2O_5$ and it's molecular mass is 294.3 gram per mol.

We have been given with 4.50 mg of aspartame and asked to calculate the moles. For mass to moles conversion we divide the given mass in grams by molar mass.

Since, the mass is given in mg, we need to convert it to g first.

1 mg = 0.001 g

So, $4.50mg(\frac{0.001g}{1mg})$

= 0.00450 g

Now let's calculate the moles on dividing the grams by molar mass as:

$0.00450g(\frac{1mol}{294.3g})$

= $1.53*10^-^5mol$

Hence, $1.53*10^-^5mol$ are present in 4.50 mg of aspartame.

4 0

4 years ago

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