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3 years ago

The Law of Superposition states that

Chemistry

1 answer:

SCORPION-xisa [38]3 years ago

8 0

C. older material is located below younger material

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What is the wavelength of radiation that has a frequency

White raven [17]

Answer:

$\lambda = \frac{c}{\nu}$

Explanation:

The wavelenght of a radiation is inversely proportional to its frequency. It can be estimated by the following formula:

$\lambda = \frac{c}{\nu}$

Where:

$\lambda$ is the wavelenght
$\nu$ is the frequency
$c$ is the speed of light (arroung 300000 km/s)

5 0

3 years ago

The outside boundary of an animal cell

Wewaii [24]

Plasma membrane is the answer

6 0

3 years ago

(f) Which of the following alkenes is the major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol?

belka [17]

Answer:

D) 2-methylpent-2-ene

Explanation:

This is an elimination reaction of Halogenoalkane. 2-bromo-2-methylpentane when is heated with NaOH or NaOC2O5( sodium ethoxide) in ethanol will form alkene rather than alcohol.

2-methylpent-1-ene is minor product since double bond form with secondary Carbon rather than primary Carbon.

8 0

3 years ago

Read 2 more answers

Each equation is incorrect. find the errors, then rewrite and balance each equation. cl2 + nai → nacl2 + i nh3 → n + h2 na + o2

VikaD [51]

1) Balanced chemical reaction: Cl₂ + 2NaI → 2NaCl + I₂.
Chlorine and iodine are diatomic molecules.
2) Balanced chemical reaction: 2NH₃ → N₂ + 3H₂.
Nitrogen and hydrogen are diatomic molecules.
3) Balanced chemical reaction: 4Na + O₂ → 2Na₂O.
Sodium in compounds has oxidation number +1 and oxygen -2.

6 0

3 years ago

As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los

dmitriy555 [2]

Answer: For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

Explanation:

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = $\frac{2257J}{1g}\times 307g=692,899J$

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

7 0

3 years ago