Answer:
9.74 x 10^7 m/s
Explanation:
V = 27000 V
energy of electrons = e x V
K = 1.6 x 10^-19 x 27000 = 43200 x 10^-19 J
Energy = 1/2 m v^2
43200 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2
v^2 = 9.495 x 10^15
v = 9.74 x 10^7 m/s
Answer:
an atom is about a trillion times smaller then a speck of dust.
Explanation:
hope this helps :)
Answer:
h> 2R
Explanation:
For this exercise let's use the conservation of energy relations
starting point. Before releasing the ball
Em₀ = U = m g h
Final point. In the highest part of the loop
Em_f = K + U = ½ m v² + ½ I w² + m g (2R)
where R is the radius of the curl, we are considering the ball as a point body.
I = m R²
v = w R
we substitute
Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R
em_f = m v² + 2 m g R
Energy is conserved
Emo = Em_f
mgh = m v² + 2m g R
h = v² / g + 2R
The lowest velocity that the ball can have at the top of the loop is v> 0
h> 2R
Answer:
The entropy of a gas increases when it expands into a vacuum because the number of possible states increases .
Explanation:
When a gas expand in a vacuum, the molecules of the gases vibrates very fast and starting moving with higher velocity in random directions which means the level of disorder in the gases increases.
Now the possible state of the gas molecule increases such as the particle can be located at different position due to increased randomness.
<u>Entropy is the measure of this randomness and thus with this increased randomness entropy also increases.</u>
An initiator is someone who starts something. Example: She initiated the fight.
