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CaHeK987 [17]
3 years ago
6

When a Lunar Module landed on the Moon, it used thrusters to slow its descent to the surface. When other spacecraft are returned

to Earth, they use parachutes to slow their descent. Why wouldn't a parachute be useful on the Moon?
Physics
1 answer:
mote1985 [20]3 years ago
7 0
A parachute is a device designed to generate a LOT of air resistance.
Parachutes do that very well in places where there's any air to work with.
There is no air on the Moon.

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I think it’s color but not sure
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A screw is a type of simple machine. If we look closely at a screw, we see that it is really a _________ wrapped around a centra
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A baby stroller is a rest on top of a hill which is 10 m high. The stroller and baby have a mass of 20 kg. What is the potential
Anettt [7]

The potential energy is defined as the energy is contained in the body due to the height over the surface of the earth and it is calculated from the equation

PE=mgh

<em>where:</em>

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  • h: the height of the body over the earth in meters.

<em>in our problem:</em>

PE=20*9.8*10=1960 J

6 0
3 years ago
Sheila (m=56.8 kg) is in her saucer sled moving at 12.6 m/s at the bottom of the sledding hill near Bluebird Lake. She approache
balu736 [363]

Answer:

y = 54.9 m

Explanation:

For this exercise we can use the relationship between the work of the friction force and mechanical energy.

Let's look for work

      W = -fr d

The negative sign is because Lafourcade rubs always opposes the movement

On the inclined part, of Newton's second law

Y Axis  

      N - W cos θ  = 0

The equation for the force of friction is

      fr = μ N

      fr = μ mg cos θ

We replace at work

     W = - μ m g cos θ  d

Mechanical energy in the lower part of the embankment

      Em₀ = K = ½ m v²

The mechanical energy in the highest part, where it stopped

     Em_{f} = U = m g y

     W = ΔEm =  Em_{f} - Em₀

    - μ m g d cos θ = m g y - ½ m v²

Distance d and height (y) are related by trigonometry

     sin θ = y / d

     y = d sin θ

   

    - μ m g d cos θ = m g d sin θ - ½ m v²

We calculate the distance traveled

     d (g syn θ + μ g cos θ) = ½ v²

     d = v²/2 g (sintea + myy cos tee)

     d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)

     d = 1555.85 /7.8145

     d = 199.1 m

Let's use trigonometry to find the height

      sin 16 = y / d

      y = d sin 16

      y = 199.1 sin 16

      y = 54.9 m

4 0
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Label the part that make up the human heart. Drag the item on the left to the correct location on the right.
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<em>hey there! ;D</em>

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<em>hope this helps!</em>

<em>have an awesome day ;)</em>

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