Answer:
The average gauge pressure inside the vein is 110270.58 Pa
Explanation:
This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.
Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:
As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:
324 because when we use the formula for weight which is w=mg; W is weight; M is mass; G is gravity, now we multiply the gravity which is 1.62 m/s times the mass which is 200g and we will have 324. Hope it helps
Answer:
1.) answer B
2.) answer D
3.) answer A
Explanation:
In all of these problems, it is essential to draw pictures in order to understand which trigonometric function to use according to the angle that the vector in question forms with the component requested. For all of them try to picture a right angle triangle with the vector as the hypotenuse, and the components as the triangle's shorter sides. Please refer to the three pictures attached as image for this answer a,d notice that the vector quantity known for all cases is represented in red, and the component to find is represented in green.
Problem 1) : the vector velocity makes an angle of 24 degrees with the edge of the table. So picture that vector as the hypotenuse of a right angle triangle for which you know the value: 1.8 m/s
So in this case, where you know the angle, the hypotenuse, and need to find the adjacent side to the angle, you use the cosine function as follows:
requested component 
which we round to 1.6 to match answer C).
For problem 2.) wee need to find the component opposite to the given angle in the triangle for which we also know the hypotenuse. So we use the sine function as follows:
requested component 
which we round to 135.9 m to match answer D).
For problem 3.) we need to find the horizontal component to the acceleration which corresponds to the adjacent side to the known angle, so we use the cosine function as follows:
requested component 
which we round tp 7.7 to match answer A).
The star is FARTHER from Earth than the limit of our ability to measure parallax.
The NEAREST star outside the solar system has a parallax angle of 0.742 SECOND. That's like 0.000206 of a degree ! ALL other stars have SMALLER parallax.
I have no idea how they measure angles like these ... especially when the change in direction takes six months to happen !
